Refraction is the answer
Gggggt gg for the ggv. Gv. Gc. Gv. CFC. F
Answer:
The answer to your question is ΔHrxn = 0 kJ
Explanation:
Process
1.- Multiply Equation 1 by 2
2C(coal) + 2H₂O ⇒ 2CO (g) + 2H₂ ΔH rxn = 259.4 kJ
2.- Sum equation 2
CO(g) + H₂O ⇒ CO₂ (g) + H₂ (g) ΔHrxn = -41 kJ
Result
2C + 3H₂O + CO ⇒ 2CO + 3H₂ + CO₂ ΔHrxn = 218.4 kJ
Simplification
2C + 3H₂O ⇒ CO + 3H₂ + CO₂
3.- Sum equation 3
CO(g) + 3H₂ (g) ⇒ CH₄ (g) + H₂O (g) ΔHrxn = -218.4 kJ
Result
2C + 3H₂O + 3H₂ + CO ⇒ CO + 3H₂ + CO₂ + CH₄ + H₂O
Simplification
2C + 2H₂O ⇒ CO₂ + CH₄ ΔHrxn = 0 kJ
First of all, the answer has 3 places of accuracy.
The formula for pH is
pH = - log[H+]
Given: Ph = 3.20
Solution
3.20 = - log[H+]
Divide by - 1
-3.20 = log[H+]
Take the antilog of both sides
10^-3.20 = [H+]
[H+]= 6.30 * 10^-4 moles/L This is a measure of concentration.
It can also be written as 0.000630 moles/L
Answer:
Part A. 1.355 mol/L
Part B. 0.100 mol
Part C. 74.0 mL
Explanation:
Part A.
The molar mass of luminol is 177.16 g/mol, so the number of moles at 18.0 g is:
n = mass/molar mass
n = 18.0/177.16
n = 0.1016 mol
The molarity is the number of moles divided by the volume (0.075 L)
C = 0.1016/0.075
C = 1.355 mol/L
Part B.
The number of moles is the molarity multiplied by the volume, so:
n = 5.00x10⁻² mol/L * 2.00 L
n = 0.100 mol
Part C.
To prepare a solution by dilution, we can use the equation
C1V1 = C2V2
Where C1 is the concentration of the initial (stock) solution, V1 is its volume necessary, C2 is the concentration of the diluted solution, and V2 is its volume.
Thus, C1 = 1.355 M, C2 = 0.05 M, V2 = 2.00 L
1.355V1 = 0.05*2
V1 = 0.074 L
V1 = 74.0 mL
C = Carbon
CO = Carbon Monoxide
Co = Cobalt
O2 = Oxygen
So the answer is (3) CO
