Answer : The percentage aniline protonated is, 0.0209 %
Explanation :
First we have to calculate the pOH.
Now we have to calculate the hydroxide ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![5.68=-\log [OH^-]](https://tex.z-dn.net/?f=5.68%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=2.09\times 10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2.09%5Ctimes%2010%5E%7B-6%7DM)
The equilibrium chemical reaction will be:
From the reaction we conclude that,
Concentration of 
ion = Concentration of 
ion = 
Now we have to calculate the percentage aniline protonated.
Thus, the percentage aniline protonated is, 0.0209 %
Answer: 20 g
Explanation: heat received Q = m c dT
Q= 50J , dT= 25 C anc c= 0.10 J / g C
And m = Q / c dT
Answer:
False. The balanced equation should be
2KClO3-->2KCl + 3O2
it is a decomposition reaction.
Answer:
Aluminum Reacts With Hydrochloric Acid To Produce Aluminum Chloride And Hydrogen Gas. 2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g)What Mass Of H2(g) Is Required From The Reaction Of 0.75 G Of Al(s) With Excess Hydrochloric
