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olya-2409 [2.1K]
3 years ago
6

4 years ago a pint of milk

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Given-

Cost of milk 4 years ago = £1.05

To find-

Percentage increase in cost

Solution-

Increase in cost = £ ( 1.26 - 1.05 )

→ £ 0.21

Percentage increase :-

\frac{0.21}{1.05} \times 100

→ 20

Therefore, Percentage increase of the cost of milk over 4 years is <u>2</u><u>0</u><u>%</u> .

✍️ <em>By </em><em>Benjemin</em> ☺️

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Answer:

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Step-by-step explanation:

To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.

Now the expression that is given to us is:

8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2

Here we will simplify it by grouping the like terms, as follows:

8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2\\=-x^2+8x-10x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{6}{9}=-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}

So this is the required simplified form.

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