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Tju [1.3M]
3 years ago
14

Which of these pairs of elements have the same number of valence electrons?

Chemistry
2 answers:
TiliK225 [7]3 years ago
8 0
Berylium(Be) and calcium(Ca)
disa [49]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

It is known that elements of same group tend to possess same number of valence electrons. As a result, they show same chemical properties.

Phosphorous (P) and chlorine (Cl) belongs to third period. Valence electrons of phosphorous are 5 and chlorine has 7 valence electrons.

Beryllium (Be) and Calcium (Ca) are group 2 elements and both of them have two valence electrons.

Helium (He) is a noble gas and it does not have any valence electrons.

Oxygen (O) has six valence electrons and carbon (C) has 4 valence electrons.

Therefore, we can conclude that berylium (Be) and calcium (Ca) is the pairs of elements have the same number of valence electrons.

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How much heat must be transferred to 1600 g of iron to change the iron's
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Answer:

A. 8600 J

General Formulas and Concepts:

<u>Thermochemistry</u>

Specific Heat Formula: q = mcΔT

  • q is heat (in J)
  • m is mass (in g)
  • c is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C)

Explanation:

<u>Step 1: Define</u>

[Given] <em>m</em> = 1600 g

[Given] ΔT = 214 °C - 202 °C = 12 °C

[Given] <em>c</em> = 0.450 J/g °C

[Solve] <em>q</em>

<u>Step 2: Find Heat</u>

  1. Substitute in variables [Specific Heat Formula]:                                           q = (1600 g)(0.450 J/g °C)(12 °C)
  2. Multiply [Cancel out units]:                                                                             q = (720 J/°C)(12 °C)
  3. Multiply [Cancel out units]:                                                                             q = 8640 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

8640 J ≈ 8600 J

Topic: AP Chemistry

Unit: Thermodynamics

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Explanation:

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