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KiRa [710]
3 years ago
10

Which statement BEST explains whether or not matter is conserved in this chemical reaction?

Physics
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

tex]{\huge{\underline{\small{\mathbb{\pink{REFER \ TO \ THE \ ATTACHMENT}}}}}}[/tex]

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A 2600-m-high mountain is located on the equator. how much faster does a climber on top of the mountain move than a surfer at a
puteri [66]

The climber move 0.19 m/s  faster than surfer on the nearby beach.

Since both the person are on the earth, and moves with the constant angular velocity of earth, however there linear velocity is different.

Number of seconds in a day, t=24*60*60=86400 sec

The linear speed on the beach is calculated as

V1=\frac{2πr}{t}

Here, t is the time

Plugging the values in the above equation

V1=\frac{2π*6.4*10^6}{86400}=465.421 m/s

Velocity on the mountain is calculated as

V2=\frac{2π(r+h)}{t}

Plugging the values in the above equation

V2=\frac{2π(6.4*10^6+2600}{86400}=465.61 m/s

Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s

5 0
3 years ago
A 3.00 kg object is moving in the XY plane, with its x and y coordinates given by x = 5t³ !1 and y = 3t ² + 2, where x and y are
Hatshy [7]

Answer:

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of x= 5t^3+1

Coordinate of position of y=3t^2+2

Time = 2.00 s

We need to calculate the acceleration

a = \dfrac{d^2x}{dt^2}

For x coordinates

x=5t^3+1

On differentiate w.r.to t

\dfrac{dx}{dt}=15t^2+0

On differentiate again w.r.to t

\dfrac{d^2x}{dt^2}=30t

The acceleration in x axis at 2 sec

a = 60i

For y coordinates

y=3t^2+2

On differentiate w.r.to t

\dfrac{dy}{dt}=6t+0

On differentiate again w.r.to t

\dfrac{d^2y}{dt^2}=6

The acceleration in y axis at 2 sec

a = 6j

The acceleration is

a=60i+6j

We need to calculate the net force

F = ma

F = 3.00\times(60i+6j)

F=180i+18j

The magnitude of the force

|F|=\sqrt{(180)^2+(18)^2}

|F|=180.89\ N

Hence, The net force acting on this object is 180.89 N.

3 0
4 years ago
If a 370 KG missile is flying at a speed of 220 m/s , then what is it’s kinetic energy
lidiya [134]

Answer:

8954000 J

Explanation:

The formula to find kinetic energy is:

<em>Kinetic energy = </em>\frac{1}{2}<em> × mass × (velocity)²</em>

So, Kinetic energy = \frac{1}{2} × 370 × (220)²

Kinetic energy = 8954000 J

4 0
2 years ago
Please help me understand this
zloy xaker [14]

Answer: Can't see the photo clearly.

6 0
2 years ago
In the graph below, why does the graph stop increasing after 30 seconds?
stepladder [879]

Answer:

The answer is "Option C".

Explanation:

It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.

hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.

A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.

6 0
3 years ago
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