The answer is:
True
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Answer:
Explanation:
It is given that,
Mass of the train car, 
Initial speed of the train car, 
Initial speed of the second car, 
After the collision, both cars stick together and move off with a speed of 4.00 m/s, V = 4 m/s
Let
is the mass of the second car. It can be calculated using the conservation of momentum. In case of inelastic collision, after collision both objects move with a common speed.






So, the mass of the second car is 33833.33 kg. Hence, this is the required solution.
Answer:A) 19.8 seconds
B) 467.5 metres
Explanation: 100km/hr = 27.78m/s
So, it covers 27.78 metres in one second
Take the time it would cover 550m as x
Therefore 27.78m = 1second
550m = x
Cross multiplying
27.78x = 550m
Divide both sides by the coefficient of x
x = 550÷27.78
x = 19.8seconds
B) distance = speed × time
Speed = 85km/hr = 23.61m/s
Time = 19.8seconds
Therefore,
Distance = 23.61 × 19.8
Distance = 467.5m
Final speed after collision with the wall

before collision the speed of ball initially

time taken for the collision

now as per the formula of acceleration we know that

now plug in all values in it


so acceleration is - 5 m/s/s for above situation