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Serhud [2]
3 years ago
7

What type of waves does not need a medium to travel through?

Physics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer: Electromagnetic waves

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

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The continental ...........
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A 200-kg boulder is 1000-m above the ground. what is its potential energy?
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Explanation:

PE = mgz = 200 * 9.81 *1000 = 1962 KJ

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Helium gas is in a cylinder that has rigid walls. If the pressure of the gas is 2.00 atm, then the root-mean-square speed of the
aivan3 [116]

Answer:

p=p_{2}-p_{1}=2.9188atm

Explanation:

First step

To calculate by how much the pressure has been increased we must find a relation between Vrms and the pressure p

V_{rms}=\sqrt{\frac{3RT}{M} } \\

Where M is molar mass,R is gas constant and T is temperature

As R and M is constant so we obtain

Vrams∝√T

Second step

From Ideal gas law we know that

pV=nRT\\

we will find that

p∝T

So from first and second step, we can obtain that

Vrms∝√p

And a relation between both of them could be given by:

\frac{V_{rms1} }{V_{rms2}}=\frac{\sqrt{p_{1} } }{\sqrt{p_{2}} }\\  p_{2}=[\frac{(V_{rms1})^{2}  }{(V_{rms2})^{2} }]p_{1}\\  p_{2}=\frac{(276m/s)^{2} }{(176m/s)^{2} } (2atm)\\p_{2}=4.9188atm

The pressure is increased to 4.1988 atm, so the amount will be given by:

p=p_{2}-p_{1}=4.9188atm-2atm\\p=p_{2}-p_{1}=2.9188atm

7 0
3 years ago
Complete the sentence with the word "element" or "compound."
harina [27]

Answer:

"element"= There are four basic sentence patterns based on sentence construction element

7 0
3 years ago
Read 3 more answers
A wild ride a car in a roller coaster moves along a track that consists of a sequence of ups and downs. let the x axis be parall
Inessa05 [86]

solution:

write the coordinates of the points A and B  

A= (0,0,14)ft

B= (5,-6,0)ft

write the position vector of a with recpect to b

R_{BA}=(0-5)i+(0-(-6))j+(14-0)k

     =-5i+6k+14k

calculation of a magnitude of the vector R_{BA}

\left | R_{BA} \right |=\sqrt{(-5)^2+6^2+14^2}

                      =\sqrt{25+36+196}

                      =16.031ft

calculation of the unit vector  

\frac{-5i+6k+14k}{16.031}

calculation of the force

F_{BA}=R_{BA}U_{BA}  

here, F_{BA} is the magnitude of the force.

substitute 350lb for F_{BA} and (\frac{-5i+6k+14k}{16.031}) for U_{BA}.

F_{BA} = 350 x (\frac{-5i+6k+14k}{16.031})

      =-109.2i+131j+305.7k lb

8 0
4 years ago
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