The answer is 18.02 grams
Answer:
US₂
Explanation:
Uranium sulfide (US₂)
Uranium atomic symbol = U
Sulfur atomic symbol = S
Uranium valency = +4
Sulfur valency = -2
So;
Uranium sulfide (US₂)
Answer:
1.75 moles of H₂O
Solution:
The Balance Chemical Equation is as follow,
N₂H₄ + O₂ → N₂ + 2 H₂O
Step 1: Calculate the Limiting Reagent,
According to Balance equation,
32.04 g (1 mol) N₂H₄ reacts with = 32 g (1 mol) of O₂
So,
28 g of N₂H₄ will react with = X g of O₂
Solving for X,
X = (28 g × 32 g) ÷ 32.04 g
X = 27.96 g of O₂
It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.
Step 2: Calculate moles of Water produced,
According to equation,
32.04 g (1 mol) of N₂H₄ produces = 2 moles of H₂O
So,
28 g of N₂H₄ will produce = X moles of H₂O
Solving for X,
X = (28 g × 2 mol) ÷ 32.04 g
X = 1.75 moles of H₂O
<span>Van der waals interactions are the electrical interactions between two or more atoms and even molecules but the inter-molecular attractions between the molecules are not exactly strong, in fact they are the weakest. And these Van der waals interactions are happened when electrons are not symmetrical distributed in a molecule.</span>
Answer:
The mass of xenon in the compound is 2.950 grams
Explanation:
Step 1: Data given
Mass of XeF4 = 4.658 grams
Molar mass of XeF4 = 207.28 g/mol
Step 2: Calculate moles of XeF4
Moles XeF4 = mass XeF4 / molar mass XeF4
Moles XeF4 = 4.658 grams / 207.28 g/mol
Moles XeF4 = 0.02247 moles
Step 3: Calculate moles of xenon
XeF4 → Xe + 4F-
For 1 mol xenon tetrafluoride, we have 1 mol of xenon
For 0.02247 moles XeF4 we have 0.02247 moles Xe
Step 4: Calculate mass of xenon
Mass xenon = moles xenon * molar mass xenon
Mass xenon = 0.02247 moles * 131.29 g/mol
Mass xenon = 2.950 grams
The mass of xenon in the compound is 2.950 grams
