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makvit [3.9K]
3 years ago
14

Which units express specific heat capacity?

Chemistry
2 answers:
anastassius [24]3 years ago
7 0

Answer:

b

Explanation:

J/(gi°C), J/(giK), cal/(gi°C), cal/(giK)

mixer [17]3 years ago
5 0

Answer : The correct option is \frac{J}{g^oC},\frac{J}{gK},\frac{cal}{g^oC},\frac{cal}{gK}.

Explanation :

Specific heat capacity : It is defined as the amount of heat required to raise the temperature of one gram of substance by one degree Celsius.

Formula used :

q=mc\Delta T\\c=\frac{q}{m\Delta T}

where,

q = heat required

m = Mass

c = specific heat capacity

\Delta T = change in temperature

The unit of heat are expressed in terms of Joules, calories.

The unit of temperature are expressed in terms of degree Celsius, kelvin.

It is expressed as \frac{J}{g^oC},\frac{J}{gK},\frac{cal}{g^oC},\frac{cal}{gK}.

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1. 100gm of a 55% (M/M) nitric acid solution is to be diluted to 20% (M/M) nitric acid.
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Answer:

The volume of water to be added is 0.175 liters of water

Explanation:

The given concentration of the nitric acid = 55% (M/M)

The mass of the nitric acid solution = 100 gm

The concentration solution is to diluted to = 20% (M/M)

The 100 g 55%(M/M) nitric acid solution gives 55g nitric acid in 100 g of solution

Therefore, to have 20% (M/M) nitric acid solution with the 55 g nitric acid, we get

Let "x" represent the volume of the resulting solution, we have;

20% of x = 55 g of nitric acid

∴ 20/100 × x = 55 g

x = 55 g × 100/20 =  275 g

The mass of extra water to be added = The mass of the 20%(M/M) solution solution of nitric acid - The current mass of the 55%(M/M) solution of nitric acid

The mass of extra water to be added = 275 g - 100 g = 175 g

Volume = Mass/Density

The density of water ≈ 1 g/ml

∴ The volume of water to be added that gives 175 g of water =  175 g/(1 g/ml) = 175 ml. = 0.175 l

The volume of water to be added = 0.175 liters of water.

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