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Levart [38]
2 years ago
9

Exactly 1 mol Hg2(NO3)2 contains how many moles of Hg , N , and O ?

Chemistry
1 answer:
marin [14]2 years ago
6 0

In exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.

Since the molecular formula of Hg₂(NO₃)₂ shows that for every mole of the substance, we have 2 moles of Hg, 2 moles of N and 6 moles of O.

So, in exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.

Learn more about number of moles here:

brainly.com/question/3935424

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In the bromination reaction of ​trans​-cinnamic acid, a student started with 300 mg oftrans​-cinnamic acid and excess bromine. T
jonny [76]

Answer:

The percentage yield is= 80%

Explanation:

% yield= actual yield/theoretical yield ×100

From The question

Actual yield= 240mg

Theoretical yield= 300mg

%yield= 240/300×100= 80%

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3 years ago
Which organism does not have a tail or black hair​
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7 0
3 years ago
NaCl has a Delta. Hfus = 30. 2 kJ/mol. What is the mass of a sample of NaCl that needs 732. 6 kJ of heat to melt completely? Use
tia_tia [17]

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

The heat of fusion has been the amount of heat required to convert  1 mole of substance into solid to liquid state.

The heat required has been given as:

Q=m\Delta H

<h3>Computation for the mass of NaCl</h3>

The given solution has heat of fusion, \Delta H_{fus}=30.2\rm kJ/mol

The heat required to melt the sample has been, Q=732.6\;\rm kJ/mol

Substituting the values for the mass of NaCl

\rm 732.6\;kJ/mol=Mass\;\times\;30.2\;kJ/mol\\\\&#10;Mass=\dfrac{732.6}{30.2}\;g\\\\&#10; Mass=24.3\;g\\

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

Learn more about heat of fusion, here:

brainly.com/question/87248

5 0
3 years ago
Which of the Following Correctly Balances this Equation? _H2+_Cl2 --&gt; _HCl
Scorpion4ik [409]
2 hydrogen and 2 chlorine on the reactant side(left of the arrow)
There is only 1 H and 1Cl on the products side so the balanced equation would be;
H2 + Cl2 —> 2 HCl
7 0
3 years ago
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