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emmainna [20.7K]
3 years ago
15

B. 239/94 Pu 4/2 He +​

Chemistry
1 answer:
dedylja [7]3 years ago
4 0

Answer:

im thinking  its 362x

Explanation:

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What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p
zubka84 [21]

<u>Given:</u>

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

<u>To determine:</u>

The final concentration of KIO3 i.e. M2

<u>Explanation:</u>

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

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a 32 gram radioactive sample has a half-life of 2 days how much of the original sample remains after 6 days
bixtya [17]
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3 0
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