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Helen [10]
2 years ago
5

A test is worth a total of 150 points and contains 70 questions. Some of the questions are worth 2 points and some are worth 4 p

oints.
The test has
questions worth 2 points and
questions worth 4 points.

Emma answered a certain number of questions correctly and scored 100 points. If she answered 46 questions worth 2 points correctly, the number of questions worth 4 points she answered correctly is
.
Mathematics
1 answer:
GarryVolchara [31]2 years ago
7 0

Answer:

46 \times 2 = 92 \: points \\ 100 - 92 = 8 \: points \\ 4 \times 2 = 8 \\ two \: of \: the \: 4 \: points \: questions \:  \\ were \: answered \: correctly

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Answer:

x=119119,\;\;\;y=119119

Step-by-step explanation:

Let the x be the first number, y be the second number and p be the product of the first and second number.

i.e  x+y=238238   \Rightarrow x=238238-y

      p=xy

   \Rightarrow p=(238238-y)y\\\Rightarrow p=238238y-y^2

\Rightarrow \frac{dp}{dy} =238238-2y\\\Rightarrow 0=238238-2y\\\Rightarrow 2y=238238\\\Rightarrow y=119119

Now,

x=238238-119119\\\\ \Rightarrow x=119119

Hence, x=119119,\;\;\;y=119119

   

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\bf \qquad \textit{Compound Interest Earned Amount}\\\\A=P\left(1+\frac{r}{n}\right)^{nt}\quad \begin{cases}A=\textit{accumulated amount}\to &8000\\P=\textit{original amount deposited}\\r=rate\to 5\%\to \frac{5}{100}\to &0.05\\n=\begin{array}{llll}\textit{times it compounds per year}\\\textit{is only once, so}\end{array}\to &1\\t=years\to &3\end{cases}

\bf 8000=P\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies 8000=P(1.05)^3\implies \cfrac{8000}{1.05^3}=P\\\\\\6910.70\approx P\implies  \stackrel{\textit{rounded up}}{6911 = P}\qquad  therefore\qquad 6911~~\leqslant ~~P

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Answer:

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