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baherus [9]
3 years ago
9

A ball of mass 0.1kg is thrown vertically upwards with an initial velocityof 80 m/s. calculate the pontential energy (i) half wa

y up (ii) at its maximum height. what is its kinetic energy as it leaves the ground​
Physics
1 answer:
gregori [183]3 years ago
6 0

Answer:

Stated below:

Explanation:

Let's calculate the maximum height

.

H=v^2/2g=320mH=v  

2

/2g=320m

PE=mgh=0.1*10*320=320 J

at halfway up PE will be half of max = 320/2=160 J

KE will be equal to PEmax=320 J.

Hope I helped! ☺

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