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RideAnS [48]
2 years ago
10

The Toro Co. makes Toro snowblowers, Toro lawn mowers, Toro yard tools, and Toro sprinkler systems. The Toro Co. uses a ________

strategy.
Physics
1 answer:
Natasha_Volkova [10]2 years ago
7 0

The strategy:

The Toro Co. uses a family branding strategy.

What is family branding?

Family branding is a marketing tactic that emphasizes promoting the parent brand name while simultaneously advertising a family of goods and services. It is also sometimes referred to as "umbrella branding," which implies that all branding initiatives are carried out under the parent brand name.

In this case, the parent brand is Toro. The "Toro Motor Company" was founded in 1914 with the goal of producing tractor engines for The Bull Tractor Company. By acquiring Whirlwind Corp., Toro joined the push mower industry in 1948.

All the stated types of machinery are provided under the name of Toro, suggesting that the parent brand name is used to promote sales.

Thus, it is a case of family branding.

To know more about The Toro Co. refer to:

brainly.com/question/15971507

#SPJ4

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Does earth's atmospheric pressure cause gravity?
konstantin123 [22]
The Earth's atmosphere is kept close to Earth by gravity. Just as the Earth's gravity keeps you firmly on the ground, it also acts on the gases of the Earth's atmosphere, holding it in place and allowing us to breathe.
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4 years ago
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How many neutrons does element X if it’s atomic number is 28 and its mass number is 87
Sergeeva-Olga [200]

the answer is 59 neutrons


7 0
3 years ago
21. True or False: Static friction prevents you from slipping when you walk on a sidewalk.​
Sloan [31]

Answer:

Yes it is true because static friction help us to make grip between the foot and the ground surface

Explanation:

Yes, as we know that the friction between two surface is of two types

1) Static friction

2) Kinetic friction

When two surface moves relative to each other then the friction force between two surface is kinetic friction and it always opposes the relative motion of two rough surface

While when one surface has tendency to move with respect to its contact surface but if it can not move on it then in this case it is static friction

So relative motion is not possible in this type of friction

So static friction helps to prevent slipping

3 0
4 years ago
A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 64 feet per second. The d
-BARSIC- [3]

Answer:

a) t=6.37s

b) t=3.3333s

Explanation:

The knowable variables are the initial hight and initial velocity

s_{o}=80ft

v_{os}=64ft/s

The equation that describes the motion of the ball is:

s=80+64t-16t^{2}

If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.

0=80+64t-12t^{2}

a) Solving for t, we are going to have two answers

t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

a=-16

b=64

c=80

t=-1.045 s or t=6.378s

<em><u>Since time can not be negative the answer is t=6.378s </u></em>

b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too

First of all, we need to find the maximum hight and how much time does it take to reach it:

v_{y}=v_{o}+gt

at maximum point the velocity is 0

0=64-32.2t

Solving for t

t=1.9875 s

Now, we must know how much distance does it take to reach maximum point

s=0+64t-16t^{2} =64(1.9875)-12(1.9875)^{2} =80ft

So, the ball pass the top of the building on its way down at 160 ft

160=80+64t-16t^{2}

Solving for t

t=2s or t=3.333s

Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building

4 0
3 years ago
Read 2 more answers
Let r denote the distance between the center of the earth and the center of the moon. What is the magnitude of the acceleration
stepan [7]

Answer:

The magnitude of the acceleration ae of the earth due to the gravitational pull of the moon is \mathbf{3.3187\times10^{-5}}\frac{m}{s^{2}}

Explanation:

By Newton's gravitational law, the magnitude of the gravitational force between two objects is:

F=G\frac{Mm}{r^{2}}(1)

With G the gravitational constant, M the mass of earth, m the mass of the moon and r the distance between the moon and the earth, a quick search on physics books or internet websites give us the values:

M=5.972\times10^{24}\,kg

m=7.34767309\times10^{22}\,kg

r=384400\,km

G=6.674\times10^{-11}\,\frac{N\,m^{3}}{kg^{2}}

Using those values on (1)

F=(6.674\times10^{-11})*\frac{(5.972\times10^{24})(7.34767309\times10^{22})}{(384400\times10^{3})^{2}}

F\approx1.98193\times10^{20}N

Now, by Newton's second Law we can find the acceleration of earth ae due moon's pull:

F=M*ae\Longrightarrow ae=\frac{F}{M}=\frac{1.98193\times10^{20}}{5.972\times10^{24}}\approx\mathbf{3.3187\times10^{-5}}

6 0
4 years ago
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