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Yakvenalex [24]

2 years ago

14

What distance was used to define the astronomical unit (AU)

1 answer:

scoundrel [369]2 years ago

5 0

<h2>approximately 93 million miles Definition of astronomical unit. For general reference, we can say that one astronomical unit (AU) represents the mean distance between the Earth and our sun. An AU is approximately 93 million miles (150 million km). It's approximately 8 light-minutes.</h2>

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N is an integer, write down the values of n such that -15<3n<6

Ira Lisetskai [31]

-15 < 3n < 6

Divide all sides by 3

-5 < n < 2

Now you need all integers between -5 and 2.

-4, -3, -2, -1, 0, 1

3 0

3 years ago

0.5x + 4 + 0.9x = x + 5

Law Incorporation [45]

Answer:

x=2.5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Factorize completely the following algebra expression :<br>81x^4-16y^8

ohaa [14]

Here’s your answer the A/= it means the answer is okay.

6 0

2 years ago

Select all the expressions that are equivalent to −5/6 / -1/3

Sindrei [870]

Step-by-step explanation:

We need to find an expression for $\dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}$ .

We can solve it as follows.

We know that,

$\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}$

So,

$\dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}=\dfrac{-5}{6}\times -3\\\\=\dfrac{5}{2}$

or

$=2\dfrac{1}{2}$

Hence, this is the required solution.

3 0

2 years ago

Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)

andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR= $\sqrt{(-3-7)^2+(0-(-10))^2}$

QR= $\sqrt{(-10)^2+(10)^2}$

QR= $\sqrt{100+100}$

QR= $\sqrt{200}$ --------------------------(1)

QR=14.142136

RS= $\sqrt{(9-(-3))^2+(-8-0)^2}$

RS= $\sqrt{(12)^2+(-8)^2}$

RS= $\sqrt{144+64}$

RS= $\sqrt{208}$ ---------------------------(2)

RS=14.422205

QS= $\sqrt{(7-9)^2+(-10-(-8))^2}$

QS= $\sqrt{(-2)^2+(-2)^2}$

QS= $\sqrt{4+4}$

QS= $\sqrt{8}$ -------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

$RS^2 = QR^ +QS^2$

Substituting the values,

$(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2$

$208 = 200 +8$

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

8 0

3 years ago