Question

what is the coefficient of static friction between a load of mass 2 kg and the horizontal surface if the limited frictional force is 10N​

Answer 1

Answer:

The surface exerts an upward normal force N such that the net vertical force on the mass is

∑ F = N - mg = 0

where m = 2 kg and g is the acceleration due to gravity. So

N = (2 kg) (9.8 m/s²) = 19.6 N

The frictional force then has magnitude µ (19.6 N), where µ is the coefficient of static friction. If the maximum magnitude of static friction is to be 10 N, we have

10 N = µ (19.6 N)

===>   µ = (10 N)/(19.6 N) ≈ 0.51