Change in velocity of larger moose: (1/3)v - v = -(2/3)v
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2
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Answer:

Explanation:
We have given number of turns N = 560
Inductance L = 8.9 mH
Current through the coil = 7 mA
Inductance of the coil is given as 
Where N is number of turns I is current and
is flux
So 
-40 c = -40 f but k would be 233.15
Answer:
The velocity will be "76.8 m/s".
Explanation:
The given values are:
Acceleration,
a = 2.4 m/s²
Time,
t = 32 seconds
By equation of motion,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 