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GalinKa [24]
3 years ago
10

On the surface of Earth, the force of gravity acting on one kilogram is: *

Physics
1 answer:
Murrr4er [49]3 years ago
4 0

Your answer would be:

Option (B) : 2.2 Pounds

Anyways stan LOONA

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find the rate of positive acceleration of an automobile which went from a complete stop to a velocity of 30 meters per second in
maks197457 [2]

Answer:

3 m/s^2

Explanation:

acceleration= Change in velocity/time

= 30-0 / 10

= 30/10

=3 m/s^2

3 0
3 years ago
A truck is moving with a certain uniform velocity. It is accelerated uniformly by 0.75 m/s^2. After 20 seconds , the velocity be
scoundrel [369]

Answer:

Vi = 5 m/s

Explanation:

let (a) acceleration = 0.75 m/s²

(t) time = 20 seconds

Vf = final velocity = 72 km/hr  (convert to m/s to units consistency = 20 m/s)

find Initial velocity (Vi)

       Vf - Vi

a =  -----------

             t

Vi = Vf - (a * t)  = 20 - (0.75 * 20)

Vi = 5 m/s

5 0
3 years ago
Which of the following can be determined by studying the spectrum of a star?
Alex73 [517]
The right answer is 
  
all of the above 
 
good luck

3 0
3 years ago
A tin atom has 50 electrons. Electrons in the ________ subshell experience the lowest effective nuclear charge.
Alexus [3.1K]

Answer:

5p

Explanation:

We are given that a tin has 50 electrons.

We have to find in which subshell electrons experience the lowest effective nuclear charge.

We know that the electron in outermost shell experience the lowest effective nuclear charge.

Electronic configuration is given by

50=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^2

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.

Answer: 5p

5 0
3 years ago
Help me plzzz<br>And thank u​
GuDViN [60]

Answer:

$ 1.1

Explanation:

From the question given above, the following data were obtained:

Cost per kWh = $ 0.1

Current (I) = 10 A

Voltage (V) = 220 V

Time (t) = 5 h

Cost of operation =?

Next, we shall determine the power the electric oven. This can be obtained as follow:

Current (I) = 10 A

Voltage = 220 V

Power (P) =?

P = IV

P = 10 × 220

P = 2200 W

Next, we shall convert 2200 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

2200 W = 2200 W × 1 KW / 1000 W

2200 W = 2.2 KW

Thus, 2200 W is equivalent to 2.2 KW.

Next, we shall determine the energy consumed by the electric oven. This can be obtained as follow:

Power (P) = 2.2 KW

Time (t) = 5 h

Energy (E) =?

E = Pt

E = 2.2 × 5

E = 11 KWh

Finally, we shall determine the cost of operation. This can be obtained as follow:

1 KWh cost $ 0.1

Therefore,

11 KWh will cost = 11 × 0.1

11 KWh will cost = $ 1.1

Therefore, the cost of operating the electric oven is $ 1.1

5 0
2 years ago
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