Answer:
I'm pretty sure the answer is runoff
<span>One end of a uniform meter stick is placed against a vertical wall. The other end is held by a lightweight cord that makes an angle, theta, with the stick. The coefficient of static friction between the end of the meter stick and the wall is 0.390. A. what is the maximum value...</span>
The answer to your question is AB is 50 kilometers.
50 kilometers
Answer:
v = 2.33 103 m / s
Explanation:
The magnetic force is
F = q v x B = i L X B
Where L is wire length and B the magnetic field
Let's calculate the value of the force
F = i L B
Now we can calculate the acceleration using Newton's second law
F = m a
a = F / m
Density is
ρ = m / V
V = π r² L
ρ = m / π r² L
m = ρ π r² L
a = I L B / (ρ π r² L)
a = 10 10³ 2.0 / (8960 π (5.1 10⁻⁴)²)
a = 2.73 10⁶ m/s²
Having the acceleration we use the kinematic equation
v² = v₀² + 2 a x
v = √ 2 ax
v = √ (2 2,723 10⁶ 1.0)
v = 2.33 103 m / s