Answer:
6.50 g of Hydrogen
Explanation:
We know that in every 20.0g of sucrose, there are 1.30g of hydrogen.
We now have 100.0g of sucrose. 100.0g is 5x larger than the 20.0g sample, which is a 5 : 1 ratio. Applying this ratio to the amount of hydrogen, we would have 5*1.3g of hydrogen in the 100.0g of sucrose.
5*1.3 = 6.5, so our answer is that there are 6.50g of hydrogen in 100.0g of sucrose.
Hope this helps!
Answer:
Dark matter makes up 85% of the mass of the universe. Dark matter is not directly observable because it doesn't interact with any electromagnetic wave. In the development of the universe, without dark matter, the universe will not function, move or rotate as it does now (this speculation led to the quest to find the anomaly of mass and energy in the known universe, eventually leading to the idealization of dark matter) and will not have enough gravitational force to hold it together. After the big bang,<em> the presence of dark matter and energy ensured that the newly formed universe didn't just float away, rather, it provided enough gravitational force to hold the universe while still allowing it to expand sufficiently</em>.
The development of the universe would have been different without the universe in the sense that the young universe won't have enough mass to hold it together, and the universe would have simply floated apart. The behavior of the universe would have been different from what we observe now, and some physical laws that applies now will not apply to the universe.
Answer:
F = ma or Force = mass x acceleration.
Explanation:
Newtons second law is about the force put onto an object. To find this you would use the formula:
Force is equal to mass times acceleration (F=ma)
The energy of the carbide released is 7262.5MJ.
<h3>What is the energy?</h3>
We know that the reaction between calcium oxide and carbon occurs in accordance with the reaction; 
. The reaction is seen to produce 464.8kJ of energy per mole of carbide produced.
Number of moles of 
produced = 1000 * 10^3 g/64 g/mol
= 15625 moles of calcium carbide
If 1 mole of transfers 464.8 * 10^3 J
15625 moles of calcium carbide transfers 15625 moles * 464.8 * 10^3 J/ 1 mol
= 7262.5MJ
Learn more about reaction enthalpy:brainly.com/question/1657608
#SPJ1
Answer: the minimum amount of energy required to break bonds and start a chemical reaction
Explanation: got a 100% on the quick check
