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Burka [1]
3 years ago
11

A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo

chemistry. do not include counter-ions,
e.g., na+, i-, in your answer. in cases where there is more than one answer, just draw one. move clear erase undo redo increase scale decrease scale copy paste set label more labels attributes more attributes single bond recessed bond protruding bond double bond other bond more bonds cyclohexane ring benzene ring other ring more rings bracket
b. draw the structures of the final acyl transfer products obtained.

Chemistry
1 answer:
julsineya [31]3 years ago
4 0
The reaction is shown below, Acid protonates the carbonyl oxygen and makes the carbonyl carbon more electrophilic. Water attacks on activated carbonyl group and forms a tetrahedral intermediate.

Intermediate:
                    Structure of Intermediate is shown both in 2-D and 3-D (below attached). 

Carbonyl group is regenerated with the elimination of ethanol.

Reaction is as below, The final product is carboxylic acid.

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Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

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As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

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Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

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As we know that:

[H^+][OH^-]=1\times 10^{-14}

0.200\times [OH^-]=1\times 10^{-14}

[OH^-]=5\times 10^{-14}

Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

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