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WINSTONCH [101]
3 years ago
6

Enter the molecular equation representing aqueous nitric acid and aqueous ammonia reacting. express your answer as a balanced mo

lecular equation. identify all of the phases in your answer.
Chemistry
2 answers:
NemiM [27]3 years ago
8 0

Answer : The balanced chemical reaction will be,

HNO_3(aq)+NH_3(aq)\rightarrow NH_4NO_3(aq)

Explanation :

Balanced chemical reaction : It is a reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

As per question.

When aqueous nitric acid react with aqueous ammonia then it gives ammonium nitrate as a product.

The balanced chemical reaction will be,

HNO_3(aq)+NH_3(aq)\rightarrow NH_4NO_3(aq)

This reaction is an acid-base reaction in which an acid react with a base to give salt and water as a product.

PtichkaEL [24]3 years ago
4 0
Aqueous nitric acid and aqueous ammonia reacts to form ammonium nitrate 
 HNO₃(aq)+NH₃(aq) = NH₄NO₃(aq)
 HNO₃ +NH3 = NH₄ (+) + NO₃ (-)
Therefore the net ionic equation will be;
 H⁺(aq) + NH₃ = NH₄⁺ (aq)

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C is the answer for this!
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Which of the following is an example of a pure substance? *
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Which of the following is a property of carbon atoms?
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B. They can for covalent bonds with other atoms.

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I want to know the steps.
Artyom0805 [142]

The answer for the following problem is described below.

<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>

Explanation:

Given:

enthalpy of combustion of glucose(ΔH_{f} of C_{6}H_{12} O_{6}) =-1275.0

enthalpy of combustion of oxygen(ΔH_{f} of O_{2}) = zero

enthalpy of combustion of carbon dioxide(ΔH_{f} of CO_{2}) = -393.5

enthalpy of combustion of water(ΔH_{f} of H_{2} O) = -285.8

To solve :

standard enthalpy of combustion

We know;

ΔH_{f}  = ∈ΔH_{f} (products) - ∈ΔH_{f} (reactants)

C_{6}H_{12} O_{6} (s) +6 O_{2}(g) → 6 CO_{2} (g)+ 6 H_{2} O(l)

ΔH_{f} = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]

ΔH_{f} = [6 (-393.5) + 6(-285.8)] - [0 - 1275]

ΔH_{f} = 6 (-393.5) + 6(-285.8)  - 0 + 1275

ΔH_{f} = -2361 - 1714 - 0 + 1275

ΔH_{f} =-2800 kJ

<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>

7 0
3 years ago
Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as
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The correct answer is   LiCH_{3}CH(CH_{3} )CH_{3} .

<h3>Organometallic reagent</h3>

Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.

Learn more about organometallic reagent here:

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