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mart [117]
3 years ago
13

một vật được ném từ đỉnh toàn nhà cao 20m so với mặt đát với vận tốc ban đàu 12m/s hợp với phương ngang một góc 30 độ. tính khoả

ng cách từ vị trí vật chạm đất đến chân tòa nhà (gốc O)
Physics
1 answer:
Helga [31]3 years ago
5 0

Sorry don't know which language is this can't understand O_o

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A 1500 kg car is approaching a hill that has a height of 12 m. As the car reaches the bottom of the hill it runs out of gas and
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Answer:

No, the car will not make it to the top of the hill.

Explanation:

Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.

Since Ф is the angle between the horizontal and the slope, the relationship between the angle and the slope and the height of the hill is given by

sinФ = 12/ΔX

Which gives you the slope as

ΔX = 12/sinФ

Therefore for the car to reach the top of the hill it will have to travel ΔX.

Ignoring friction the total work done is given by

W = ΔK

W = (kf - ki)

Since the car will come to a stop, kf = 0 J

W = -ki

m×g×sinФ×Δx = 1/2×m×vi^2

(9.8)×sinФ×Δx = 1/2×(10)^2

sinФΔx = 5.1

Δx = 5.1/sinФ

ΔX>>Δx Ф ∈ (0° , 90°)

(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)

Since the car can never travel the distance of the slope, it can never make it to the top of the hill.

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What's a cars net force if it's mass is 1500 kg and has a acceleration of 2 m/s (In Newton’s)
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or a roller coaster loop, if it were perfectly circular, we would have a minimum speed of vmin=√gR at the top of the loop where g=9.8m/s2 and R is the radius of the 'circle'. However, most roller coaster loops are actually not circular but more elliptical.

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