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3 years ago

Why is the element carbon-14 important for paleontologist?

Physics

2 answers:

luda_lava [24]3 years ago

6 0

Carbon-14 is important to paleontologists because it can determine how old a fossil is.

ch4aika [34]3 years ago

5 0

Answer:

carbon 14 is widely used in paleontology to know the age of objects.

Explanation:

Carbon is a fundamental part of all living beings, this element has two stable isotopes carbon 12 and carbon 13, the first being with an abundance of 98.9% and the other with an abundance of 1.1%, in addition to these there are some radioactive isotopes, that is, they decompose over time. One of the isotopes carbon 14 has a half-life of 5730 years.

The production of carbon 14 occurs naturally for cosmic radiation with nitrogen from the air, at a constant rate, which is why absorbed by living things with air and integrated into their system, when living beings die they stop absorbing this carbon 14 and the disintegration process begins. Therefore, by analyzing the amount of carbon 14 left in the sample, we can know when it died and infer how much time the sample had.

This procedure is called carbon dating 14, which is widely used in paleontology to know the age of objects.

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PLEASE HELP QUICKLY 50 POINTS<br> Fracturing can emit ______waves through the ground.

drek231 [11]

Answer:

Fracturing can emit seismic waves through the ground.

Explanation:

I believe the answer is seismic, I've studied this before.

5 0

2 years ago

(a) Consider a fusion generator built to create 3.00 GW of power. Determine the rate of fuel burning in grams per hour if the DT

Stels [109]

The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 × $10^1^3$ J/g per hour

<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>

D + T → He + n
The D-T fusion reaction results in a Helium (He) and neutron (n)

E = 17.59 MeV

Mass = 2.014u + 3.016u

= 5.030u

Energy per Kg = (17.59× $10^6$ ×1.6× $10^-^1^9$ ) ÷ ( 5.030×1.66× $10^-^2^7$ )

= 3.37× $10^1^4$ J/Kg

= 3.0× $10^9$ J/g

Rate of fuel burning in grams per hour = 3.0× $10^9$ × 3600

= 3.6×3.0× $10^1^2$

= 1.08 × $10^1^3$ J/g per hour

To learn more about fusion reactor and energy production, refer

brainly.com/question/13399644

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4 0

2 years ago

Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2

Svetllana [295]

Answer:

<u>I had to search the Figure on Google to solve this question.</u>

a) The magnitude of the force F₃ is:

$F_{3} = 87.47 N$

And the direction of F₃:

$\alpha = 79.04 ^{\circ}$ (with respect to the y-direction, in the third quadrant)

b) P = 4.22 N

Explanation:

<u>I had to search the Figure on Google to solve this question.</u>

a) We can find the force of the third person as follows:

$\Sigma F_{x} = F_{1x} + F_{2x} + F_{3x} = 0$

$\Sigma F_{y} = F_{1y} - F_{2y} + F_{3y} = 0$

So, in x-direction we have:

$\Sigma F_{x} = 45 N*cos(70) + 75 N*cos(20) + F_{3x} = 0$

$F_{3x} = -85.87 N$

In y-direction we have:

$\Sigma F_{y} = 45 N*sin(70) - 75 N*sin(20) + F_{3y} = 0$

$F_{3y} = -16.63 N$

The magnitude of the force F₃ is:

$F_{3} = \sqrt{F_{3x}^{2} + F_{3y}^{2}} = \sqrt{(-85.87 N)^{2} + (-16.63 N)^{2}} = 87.47 N$

To find the direction of F₃ we need to calculate its angle with respect to the y-direction (in the third quadrant):

$tan(\alpha) = \frac{|F_{3x}|}{|F_{3y}|} = \frac{85.87 N}{16.63 N}$

$\alpha = 79.04 ^{\circ}$

<em>b) If the third person exerts the force found in part (a) the car will stop, so the only way for the cart to accelerate at 200 m/s² is that the third person does not exert the force found in a. </em>

<u>To find the weight of the cart when it accelerates at 200 m/s², we need to consider: F₃ = 0</u>.

First, we need to find the cart's mass. Since the car is moving in the x-direction we have:

$\Sigma F_{x} = F_{1x} + F_{2x} = ma$

$45 N*cos(70) + 75 N*cos(20) = m*200 m/s^{2}$

$m = \frac{45 N*cos(70) + 75 N*cos(20)}{200 m/s^{2}} = 0.43 kg$

Now, the weight of the cart is:

$P = mg = 0.43 kg*9.81 m/s^{2} = 4.22 N$

I hope it helps you!

3 0

2 years ago

I have a project due in 3 days and I need help!

Flura [38]

1.Phases - Gas, liquid and solid. Gas, liquid, and solid are known as the three states of matter or material, but each of solid and liquid states may exist in one or more forms.

8 0

3 years ago

After combining components of two vectors to be added, it was found that the resultant vector has an x-component of -177 cm and

3241004551 [841]

The angle measured counterclockwise from the positive x-axis is θ = 50.4°

<h3>How to get the angle correspondent to a vector?</h3>

Here we know that the vector is:

V = < -177 cm, -214 cm>

To get the correspondent angle for this vector, we can think that this is the hypotenuse of a right triangle, such that the y-component and x-component are the cathetus.

Then, to get the angle (measured counterclockwise from the positive x-axis) is given by:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Tan(θ) = (-214cm)/(-177 cm)

Using the inverse tangent function we get:

Atan(Tan(θ)) = Atan((-214cm)/(-177 cm))

θ = 50.4°

So the angle is 50.4°

If you want to learn more about vectors, you can read:

brainly.com/question/3184914

8 0

2 years ago