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statuscvo [17]
3 years ago
13

A test charge is introduced into the electric field of a charge. It feels a force of 2 F where the electric feild is 4 E. What w

ould the force on the test charge be where the electric feild is 1 E
Physics
1 answer:
Elza [17]3 years ago
3 0

Answer:

0.5 F

Explanation:

since electric field is defined as force per charge!

so, force on test charge is directly proportional to electric field

here new electric field becomes 1/4 of old one

i.e, 4E-->1E

so force is also will become 1/4 of old one

i.e, 2F--> 1/4 × 2F =0.5 F

✌️:)

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Answer:

(a) Explained below

(b) v_f=0.35\ m/s

(c) Yes

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles or objects is conserved unless an external force is acting on the system. The formula for the momentum of a body with mass m and velocity v is P=mv. If there is a system of bodies, then the total linear momentum is the sum of the individual momentums

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Our m_1=98\ kg fullback runs at v_1=5\ m/s. Two two 68-kg linebackers attempt to stop him, one at -2.0 m/s and the other at -4.0 m/s. The negative value is because the run against the positive direction, taken in the direction of the fullback.

(a) Before the event, there is a total linear momentum, computed as the sum of the momentums of each player as shown

p_1=m_1v_1=(98)(5)=490 Kg\ m/s

p_2=m_2v_2=(68)(-4)=-272 kg\ m/s

p_3=m_3v_3=(68)(-2)=-136 kg\ m/s

p_t=p_1+p_2+p_3=390-272-136=82\ kg\ m/s

After the collision, all the players keep joined in one single mass of.

m_t=98+68+68=234\ kg

They will move at a speed which will be computed below

(b) The final momentum of the system is

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Since the linear momentum is conserved, the final speed v_f is common to all of the players. Let's solve to find it

\displaystyle v_f=\frac{p_f}{m_t}

\displaystyle v_f=\frac{82}{234}

v_f=0.35\ m/s

(c) Since the final speed of the players is positive, it means the touchdown was actually scored, the fullback moved forward across the goal line, the positive reference.

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