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Veseljchak [2.6K]

3 years ago

14

PLS HELP DUE IN 10 MINUTES I WILL GIVE BRAINLIEST FIVE STARS AND A THANKS NO JOKE IM RLLY DESPERATE SO PLS HELPPPPPP :c IF U DID

UR SUCH AN ANGEL AND THX

1 answer:

frutty [35]3 years ago

6 0

Answer:

-1/2

Step-by-step explanation:

counting down by 2 over one

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3 years ago

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

MAXImum [283]

<span>f(k) = k2 + 2k + 1 = (k+1)^2
The range is what the function gives to you f(k)=25=5^2 or (-5)^2
f(k)=64=8^2 or (-8)^2

You need to find the k values for these boundary values to find the domain.
Good luck :)</span>

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3 years ago

Can anyone do 25-30 (do not understand)

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3 years ago

Consider the line y = 7x-9.

KatRina [158]

$y = \frac{-1}{7}x -\frac{8}{7}$ is the equation of the line that is perpendicular to this line and passes through the point (6, -2)

y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)

<em><u>Solution:</u></em>

<em><u>Given that line is:</u></em>

y = 7x - 9

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + b ------ eqn 1

Where, "m" is the slope of line and "b" is the y intercept

On comparing eqn 1 with y = 7x - 9 we get,

m = 7

<h3><u>Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)</u></h3>

We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

$7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}$

Now find the equation of line:

$\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}$

$-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}$

$\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}$

Thus the equation of line perpendicular to given line is found

<h3><u>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</u></h3>

Slopes of parallel lines are equal

Therefore, m = 7

<em><u>Substitute m = 7 and (x, y) = (6, -2) in eqn 1</u></em>

-2 = 7(6) + b

-2 = 42 + b

b = -44

<em><u>Substitute m = 7 and b = -44 in eqn 1</u></em>

y = 7x - 44

Thus equation of line parallel to given line is found

8 0

3 years ago