Answer:
4046.56 cm3
Step-by-step explanation:
The base is made by 5 isosceles triangles, with one side of 14 cm, and the opposite angle of
. Each of the other angle is
. From there, you can calculate the height of each base triangle as in
or 9.634...cm.
Your volume will be ![5 * \frac {(14 * 9.634)} 2 * 12 = 4046.56 cm^3](https://tex.z-dn.net/?f=5%20%2A%20%5Cfrac%20%20%7B%2814%20%2A%209.634%29%7D%202%20%2A%2012%20%3D%204046.56%20cm%5E3)
Answer:
a) No
b) 42%
c) 8%
d) X 0 1 2
P(X) 42% 50% 8%
e) 0.62
Step-by-step explanation:
a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.
b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6
P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7
P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%
c) P(win first game) = 0.4
P(win second game) = 0.2
P(win both games) = P(win first game) × P(win second game) = 0.4 × 0.2 = 0.08 = 8%
d) X 0 1 2
P(X) 42% 50% 8%
P(X = 0) = P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%
P(X = 1) = [ P(lose first game) × P(win second game)] + [ P(win first game) × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%
e) The expected value ![\mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66](https://tex.z-dn.net/?f=%5Cmu%3D%5CSigma%7DxP%28x%29%3D%20%280%2A0.42%29%2B%281%2A0.5%29%2B%282%2A0.08%29%3D0.66)
f) Variance ![\sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844](https://tex.z-dn.net/?f=%5Csigma%5E2%3D%5CSigma%28x-%5Cmu%5E2%29p%28x%29%3D%20%280-0.66%29%5E2%2A0.42%2B%20%281-0.66%29%5E2%2A0.5%2B%20%282-0.66%29%5E2%2A0.08%3D0.3844)
Standard deviation ![\sigma=\sqrt{variance} = \sqrt{0.3844}=0.62](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7Bvariance%7D%20%3D%20%5Csqrt%7B0.3844%7D%3D0.62)
Only the upper-left statement is NOT true.
The value of constant a is -5
Further explanation:
We will use the comparison of co-efficient method for finding the value of a
So,
Given
![(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\](https://tex.z-dn.net/?f=%28x%5E2%20-%203x%20%2B%204%29%282x%5E2%20%2Bax%20%2B%207%29%5C%5C%3D%20x%5E2%28%282x%5E2%20%2Bax%20%2B%207%29-3x%28%282x%5E2%20%2Bax%20%2B%207%29%2B4%282x%5E2%20%2Bax%20%2B%207%29%5C%5C%3D%202x%5E4%2Bax%5E3%2B7x%5E2-6x%5E3-3ax%5E2-21x%2B8x%5E2%2B4ax%2B28%5C%5CCombining%5C%20alike%5C%20terms%5C%5C%3D2x%5E4%2Bax%5E3-6x%5E3%2B7x%5E2-3ax%5E2%2B8x%5E2-21x%2B4ax%2B28%5C%5C%3D%202x%5E4%20%2B%28a-6%29x%5E3%2B%2815-3a%29x%5E2-%2821-4a%29x%2B28%5C%5C)
As it is given that
(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28
In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x
Comparing coefficient of x^3
![a-6 = -11\\a = -11+6\\a = -5](https://tex.z-dn.net/?f=a-6%20%3D%20-11%5C%5Ca%20%3D%20-11%2B6%5C%5Ca%20%3D%20-5)
So the value of constant a is -5
Keywords: Polynomials, factorization
Learn more about factorization at:
#LearnwithBrainly
Well, number 1 is A, or p = 6t. This is because the number of points is equal to the number of touchdowns times six. *6 = (6)(1) *12 = (6)(2) *18 = (6)(3), etc