Answer:
1.54 moles of pure ethanol are present in 750mL of wine
Explanation:
The sort of concentration 12% by volume, means that in 100 mL of solution (wine) 12 mL are pure ethanol
We use the density of pure ethanol to determine the mass:
Ethanol density = Ethanol mass / Ethanol volume
Ethanol density . Ethanol volume = Ethanol mass
0.789 g/mL . 12 mL = 9.47 g of ethanol
Now we can determine the moles: 9.47 g . 1 mol / 46.06 g = 0.205 moles
Now we can make a rule of three:
In 100 mL of solution (wine) we have 0.205 moles of pure ethanol
Then, in 750 mL of solution we may have (750 mL . 0.205) / 100 = 1.54 moles
Answer:
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black hole in ourter space for the first time the scientific research
and development of the following layers lethargic
Explanation:
STUDY CORRECTION.
Answer:
there are 6.022*1023 atoms
Explanation:
32 g S * (1 mole S/32 g S) * (6.022*1023 atoms/1 mole S)= 6.022*1023 atoms
Answer:
Stroke D (Output Distance) = 0.533 meter (Approx)
Explanation:
Given:
Stroke D (Input Distance) = 0.80 meter
Mechanical advantage (MA) = 1.5
Find:
Stroke D (Output Distance) = ?
Computation of Stroke D (Output Distance) :
⇒ Stroke D (Output Distance) = Stroke D (Input Distance) / Mechanical advantage (MA)
⇒Stroke D (Output Distance) = 0.80 meter / 1.5
⇒ Stroke D (Output Distance) = 0.533 meter (Approx)
