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soldi70 [24.7K]
2 years ago
7

Gus wrote the following riddle: I am a number between 30 and 60. My ones digit is three less than my tens digit. I am a prime nu

mber.
What number does Gus’ riddle describe?
Mathematics
1 answer:
Neporo4naja [7]2 years ago
6 0

Answer: 41

Step-by-step explanation:

You might be interested in
What is a factor of 13 and 80
djyliett [7]

Answer: The only factor of 13 and 80 is 1.

Step-by-step explanation:

Factors of 13: 1, 13.

Factors of 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.

The only factor they have the same is 1.

3 0
3 years ago
(the stake is 14ft)
Kaylis [27]

Answer:

it‘s about

32.08 ft (if its not an answer choice try 32 or anywhere near that number)

Step-by-step explanation:

SO this is a simple example of triangles

We would need to find the heigh of the flagpole which is the leg of the triangle

The other side (14ft) is the 2nd leg of the triangle

And we know the hypotenuse is 35 ft

So we put that in Pythagorean Theroux and solve for the first missing leg

a^2+14^2=35^2

a^2+196=1225

a^2=1029

√1029 is about 32.08

So its about 32.08

5 0
3 years ago
What is 0.00340.78 correct to 3 significant figures? explain your answer
timurjin [86]
What is 0.00340.78 correct to 3 significant figures?

a significant fugure is when the number lean solething ,so its can anyone except 0


so if we are reducing 0.00340.78 to 3 significant number

first we have to look for the significant nulber ,which are 3,4,7,8


so the answer can be 0.0034.7


hopefully this helps
7 0
3 years ago
How many solutions are there to the equation below? 12x + 32 = 12x - 7
marshall27 [118]
0 solutions

move the x to one side, and the numbers to the other.

12x (-12x) + 32 (-32)= 12 (-12x) - 7 (-32)

12x - 12x = -7 - 32

0 = -39

0 ≠ -39

∴ you have 0 solutions

hope this helps


4 0
3 years ago
Read 2 more answers
The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source
Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

We know the total voltage is 6-3\mathbf{i}, thus:

4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

5 0
2 years ago
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