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3 years ago

(BRAINLIEST FOR CORRECT ANSWER) How does the particle structure of a solid affect its shape, volume, and compressibility?

Chemistry

1 answer:

Crazy boy [7]3 years ago

6 0

Answer:

A solid's particles fit closely together. The forces between the particles are so strong that the particles can not move freely; they can only vibrate. This causes a solid to be a stable, non-compressible shape with a definite volume.

Explanation:

I honestly don't know if that's right...

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What type of bond is between H2?<br>

Lynna [10]

Explanation:

covalent bond enjoy your anseer

6 0

3 years ago

Read 2 more answers

Ch4+202==>c02+302 what type of chemical reaction

n200080 [17]

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

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3 years ago

When 0.620 gMngMn is combined with enough hydrochloric acid to make 100.0 mLmL of solution in a coffee-cup calorimeter, all of t

OleMash [197]

Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

$Mn(s)+2HCl(aq)\rightarrow MnCl_2(aq)+H_2(g)$

Mass of solution = m

Volume of solution = 100.0 mL

Density of solution = d = 1.00 g/mL

$m=1.00 g/mL\times 100.0 mL = 100 g$

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

$q=m\times c\times (T_{final}-T_{initial})$

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = $4.18 J/^oC$

$T_{final}$ = final temperature = $23.1^oC$

$T_{initial}$ = initial temperature = $28.9^oC$

Now put all the given values in the above formula, we get:

$q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC$

$q=2,242.4 J=2.242 kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = $\frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol$

$\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol$

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

8 0

3 years ago

Under what conditions of temperature and pressure is a gas most soluble in water?

Valentin [98]

Answer:

A gas is most soluble in water under conditions of high pressure, and low temperature.

8 0

3 years ago

I have a mixture of sand salt and water from the sea. Describe in detail how I separate these three substances and explain why e

Ivanshal [37]

Answer:

You can separate a mixture of sand, salt and water by decantation and evaporation. Decantation will separate sand from salt and water. Sand remains in the original vessel, whereas salt and water is transfered to new vessel. Evaporation will separate salt from water.

3 0

2 years ago