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Ulleksa [173]
4 years ago
8

What volume of 0.812 m ammonium sulfate contains 7.65 g of ammonium ion?

Chemistry
1 answer:
Marina CMI [18]4 years ago
4 0
The ammonium ion is NH4+ which should have a molecular weight of 18g/mol. Then, the amount of ammonium ion in mol should be <span>7.65g/ (18g/mol)= 0.425 mol.
The formula for ammonium sulfate would be </span>(NH4)2SO4. For every ammonium sulfate, you need 2 ammonium ion. Then the amount of ammonium sulfate in mol should be: 0.425 mol * (1/2)= 0.2125mol

The volume of the solution would be: 0.2125mol/ (0.812 mol/liter)= 0.26169l= 261.70 ml
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8 0
3 years ago
Balance the following equations: (c) H2(g)+I2(s)⟶HI(s)H2(g)+I2(s)⟶HI(s)
kenny6666 [7]

Answer: H_2(g)+I_2(g)\rightarrow 2HI(s)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Thus in the reactants, there are 2 atoms of hydrogen and 2 atoms of iodine .Thus there has to be 2 atoms of hydrogen and 2 atoms of iodine in the product as well. Thus a coefficient of 2 is placed in front of HI.

The balanced chemical reaction is:

H_2(g)+I_2(g)\rightarrow 2HI(s)

6 0
3 years ago
matter that is composed of two or more different elements chemically combined in a fixed proportion is classified as
Helga [31]

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5 0
3 years ago
Select the correct answer.
Norma-Jean [14]

Answer:

a t o m i c w e i h g t

B

Explanation:

  1. a to m i c w e i g h t
7 0
3 years ago
A student uses a calorimeter to determine the enthalpy of dissolving for ammonium nitrate. The student fills a calorimeter with
ale4655 [162]
Enthalpy change during the dissolution process = m c ΔT,

here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
                                                                                 = -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)

Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>

7 0
3 years ago
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