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Ulleksa [173]
3 years ago
8

What volume of 0.812 m ammonium sulfate contains 7.65 g of ammonium ion?

Chemistry
1 answer:
Marina CMI [18]3 years ago
4 0
The ammonium ion is NH4+ which should have a molecular weight of 18g/mol. Then, the amount of ammonium ion in mol should be <span>7.65g/ (18g/mol)= 0.425 mol.
The formula for ammonium sulfate would be </span>(NH4)2SO4. For every ammonium sulfate, you need 2 ammonium ion. Then the amount of ammonium sulfate in mol should be: 0.425 mol * (1/2)= 0.2125mol

The volume of the solution would be: 0.2125mol/ (0.812 mol/liter)= 0.26169l= 261.70 ml
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What is the most mass of (NH4)2CO3 (H=1,C=12,N=14,O=16
Agata [3.3K]

Answer:

96.09 g/mol

Explanation:

You just need to first get the atomic weights of the elements involved. You can easily get these from your periodic table.

If you are going to do this properly, please use the weight with at least two decimal places for accuracy (e.g. 15.99 g/mol).

Also, please take note that I will be using the unit g/mol for all the weights. Thus,

Step 1

N = 14.01 g/mol

H = 1.008 g/mol

O = 16.00 g/mol

C = 12.01 g/mol

Since your compound is  

(

N

H

4

)

2

C

O

3

, you need to multiply the atomic weights by their subscripts. Therefore,

Step 2

N = 14.01 g/mol × 2 =

28.02 g/mol

H = 1.008 g/mol × (4×2) =

8.064 g/mol

 

O = 16.00 g/mol × 3 =

48.00 g/mol

C = 12.01 g/mol × 1 =

12.00 g/mol

To get the mass of the substance, we need to add all the weights from Step 2.

Step 3

molar mass of

(

NH

4

)

2

CO

3

=

(28.02 + 8.064 + 48.00 + 12.01) g/mol

=

96.09 g/mol

this is a google search and a example i hope is helps to solve

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3 years ago
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The answer is 200 J

The kinetic energy (KE) is:
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v - velocity of the object

We have:
m = 4 kg
v = 10 m/s

KE = 1/2 * 4 kg * 10² m/s
KE = 200 J
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Answer:

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Andru [333]

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Hope this helped!!!

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