All categories

3 years ago

Which of the following is an extremely reactive family of elements?

Physics

2 answers:

7nadin3 [17]3 years ago

8 0

A , noble gases this is the best answer in which I do think this is the answer I’m sorry if I got it wrong

goblinko [34]3 years ago

6 0

Answer:A) noble gases

Explanation: key word gas. if you fart it smells and other gases harm.

You might be interested in

Each of the following figures shows Earth with a different axis tilt. (Assume that Earth's rotation period is unchanged.) Each a

mart [117]

Answer:

0º - 23.5º - 45º - 90º

Explanation:

The inclination angle of the Earth's axis with respect to its orbit around the Sun, determines that the duration enters the day and the night is different.

If it is not inclined (angle 0º) the two and niches have the same hardness

If the angle were very high (about 90º) the night would be very long, about half of the orbit period about six months.

Based on this presentation we can answer the question

The Sumo exposition from highest to lowest is

0º - 23.5º - 45º - 90º

3 0

3 years ago

What type of wave does NOT need matter to carry energy? *

Blababa [14]

Answer:

I guess sound wave I s gonna be d right answer

Explanation:

cos sound doesnt has weight and occupies space

3 0

4 years ago

An attacker at the base of a castle wall 3.95 m high throws a rock straight up with speed 5.00 m/s from a height of 1.60 m above

s344n2d4d5 [400]

Answer:

a) No

b) the rock must have a minimum initial speed of 6.79m/s for it to reach the top of the building.

Explanation:

Given:

Height of the wall = 3.95m

Initial height = 1.60m

Initial speed = 5.00m/s

distance between the initial height and wall top = 3.95 - 1.60 = 2.35m

Using the formula;

v^2 = u^2 + 2as ....1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance travelled

From equation 1

s = (v^2 - u^2)/2a ...2

Since the rock t moving up,

the acceleration = -g = -9.8m/s2

s = maximum height travelled

v = 0 (at maximum height velocity is zero)

Substituting into equation 2

s = (0 - 5^2)/(2×-9.8) = 1.28m

Therefore, the maximum height is 1.28 from his initial height Which is less than the 2.35m of the wall from his initial height. So the rock will not reach the top of the wall

b) Using equation 1:

u^2 = v^2 - 2as

v = 0

a = -9.8m/s

s = 2.35m. (distance between the initial height and wall top)

u^2 = 0 - 2(-9.8 × 2.35)

u^2 = 46.06

u = √46.06

u = 6.79m/s

Therefore, the rock must have a minimum initial speed of 6.79m/s

8 0

3 years ago

i will give the brainliest answer to whoever answers this, explain how Sir William Gilbert used models in his investigation of m

levacccp [35]

Explanation:

Lodestone am iron were the only known magnetic materials in Gilbert's day, and his task was to investigate magnetism. Gilbert was so sure that the earth was a giant lodestone and used the earth as a primary reference, defining the north(magnetic) pole of a needle, or a a nail floating on a piece of cork, to be that which turns towards the Earth's north geographic pole. he wanted to prove this with a model Terella, using short pieces of iron.

7 0

3 years ago

A uniform meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 5 s. The meter stick

rewona [7]

Answer:

The new time period is $T_2 = 3.8 \ s$