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mixer [17]
4 years ago
5

) In physics, an object that is in motion is said to have kinetic energy. The following formula can be used to determine a movin

g object’s kinetic energy: KE = ½ mv2 The variables in the formula are as follows: KE is the kinetic energy, m is the object’s mass in kilograms, and v is the object’s velocity, in meters per second. Write a method named kineticEnergy that accepts an object’s mass (in kilograms) and velocity (in meters per second) as arguments. The method should return the amount of kinetic energy that the object has. Demonstrate the method by calling it in a program that asks the user to enter values for mass and velocity.
Physics
1 answer:
Otrada [13]4 years ago
5 0

Answer:

using MATLAB

%program to calculate the kinetic velocity of a body of mass

% kinetic energy is given by 1/2*(m*v^2)

%m= mass of body in kilogram

%v= velocity of body in m/s

prompt= 'mass of body=';

m= input(prompt); %command to request user to input mass value

prompt='velocity of body=';

v= input(prompt);%command to request user to input velocity value

Ke= 1/2 * m* (v^2);

display(Ke)

Explanation:

running the code, u would be prompted to input values after the equality sign, just enter without space and your result would be displayed

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A wagon of dog treats (combined mass 55 kg) is rolling at 2.1 m/s. A dog with mass 21 kg dives into the wagon, colliding with ju
Lunna [17]

Answer:

Explanation:

An impulse results in a change of momentum

If the wagon and dog both stop, they must have had equal and opposite momentums

FΔt = mΔv

F = mΔv/Δt = m(v₁ - v₀)/(t₁ - t₀)

v₁ = t₀ = 0

F = m(v₀)/t₁

F = 55(2.1)/0.1 = 1155 N

We could have also figured the dog's initial velocity and used the dog's mass in the equation as well. Result would be identical.

5 0
2 years ago
How can you tell if one object has more mass than another does, on a planet without gravity
Serhud [2]

an object is more dense if there is more weight in the same area, its because of the amount of particles and the weight of the particles. eg, 1cm cubed of gold would weigh alot more than 1cm cubed polystyrene, so gold is more dense

3 0
3 years ago
A 125 W motor accelerates a block along a level, frictionless surface at an average speed of 5.0
Lelu [443]

Answer:

25N

Explanation:

Given parameters:

Power of the motor = 125W

Average speed  = 5m/s

Unknown:

Force supplied to the motor = ?

Solution:

 Work done is the force applied to move a body through a particular distance;

         Work done  = Force x distance

Also,

        Work done  = Power x time

 

So;

             Force x distance = Power  x time

  since force is the unknown;

            Force  = \frac{Power x time}{distance}

         Speed  = \frac{distance }{time}

             Force  = \frac{Power}{speed}

Now solve;

                Force  = \frac{125}{5}    = 25N

3 0
3 years ago
A 1/40 scale model is to be used in a towing tank to study the water motion near the bottom of a shallow channel as a large barg
nadezda [96]

Answer:

I t hi ink the answer is a

Explanation:

I hoped this helpes

5 0
3 years ago
Find the electric field at a point midway between two charges of +40.0 x 10^-9 c and.+60.0 x 10^-9 c
PIT_PIT [208]
Missing part in the text: "...the charges are <span>separated by a distance of 30.0 cm."
</span>
Solution:
The point midway between the two charges is located 15.0 cm from one charge and 15.0 from the other charge. The electric field generated by each of the charges is
E=k_e \frac{q}{r^2}
where
ke is the Coulomb's constant
Q is the value of the charge
r is the distance of the point at which we calculate the field from the charge (so, in this problem, r=15.0 cm=0.15 m).

Let's calculate the electric field generated by the first charge:
E_1 = (8.99 \cdot 10^9 Nm^2 C^{-2} ) \frac{+40.0 \cdot 10^{-9} C}{(0.15 m)^2}=1.6 \cdot 10^4 N/C

While the electric field generated by the second charge is
E_2 = (8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{+60.0 \cdot 10^{-9} C}{(0.15 m)^2}=2.4 \cdot 10^4 N/C

Both charges are positive, this means that both electric fields are directed toward the charge. Therefore, at the point midway between the two charges the two electric fields have opposite direction, so the total electric field at that point is given by the difference between the two fields:
E=E_2 - E_1 = 2.4 \cdot 10^4 N/C - 1.6 \cdot 10^4 N/C = 8000 N/C
4 0
3 years ago
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