Answer:
total current = 12.417 A
so it will not fuse as current is less than 15 A
Explanation:
given data
toaster = 1140-W
blender = 270-W
lamp = 80-W
voltage = 120 V
solution
we know that current is express as
current = power ÷ voltage ......................1
here voltage is same in all three device
so
current by toaster is
I = 
I = 9.5 A
and
current by blender
I = 
I = 2.25 A
and
current by lamp is
I = 
I = 0.667 A
so here device in parallel so
total current is = 9.5 A + 2.25 A + 0.667 A
total current = 12.417 A
so it will not fuse as current is less than 15 A
Answer:
common types of topologies, and we're going to break each of them down in the guide below.
Bus topology. As the simplest design, a bus topology requires nodes to be in a linear order. ...
Ring topology. Another simple design is the ring topology. ...
Star topology. ...
Mesh topology. ...
Tree topology.
Explanation:
I believe that the correct answer you are looking for is the distance traveled
The solution to the problem is as follows:
<span>Average = 80
So Sum = 80 * 5 = 400
Mode = 88, so two results are 88 (if three results were 88, then the median would be 88).
Three results are 81, 88, and 88.
That leaves 143. We could still have one 81 score, so that leaves the lowest score as 62.
Greg is in a car at the top of a roller-coaster ride. The distance, d, of the car from the ground as the car descends is determined by the equation d = 144 - 16t2, where t is the number of seconds it takes the car to travel down to each point on the ride. How many seconds will it take Greg to reach the ground?
d = 144 - 16t2
0 = 144 - 16t2
16t^2=144
t^2=9
t=3</span>
Answer:
Rs = 0.02008 Ω = 20.08 mΩ
Explanation:
The range of an ammeter can be increased by connecting a small shunt resistance to it in a series combination. This shunt resistance can be calculated by the following formula:
where,
= value of shunt resistance = ?
= current range of ammeter = 20 mA = 0.02 A
I = Required range of ammeter = 5 A
= Resistance of ammeter = 5 ohms
Therefore,
<u>Rs = 0.02008 Ω = 20.08 mΩ</u>
