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2 years ago

What is the difference between end point and equivalence point?

Chemistry

1 answer:

xxMikexx [17]2 years ago

3 0

Answer:

The difference between the endpoint and the equivalence point is that the endpoint is the point where your indicator will show a change in colour, your equivalence point however is the point when the analyte has completely reacted with the titrant. So the endpoint is when the indicator may change colours, the equivalence point is when the analyte and titrant are stoichiometrically equal

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How likely is it that a brother or sister would be just like you.

Makovka662 [10]

Answer:

Theoretically you could be totally unrelated to your sister or share the exact same DNA as your brother. But because we are talking about so much DNA and so many different possible combinations, the percentage usually comes out to about 50%. Think about it like flipping a coin.

Explanation:

3 0

2 years ago

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A student carried out a simple distillation on a compound known to boil at 124 oc and they reported a boiling point of 116-117 o

chubhunter [2.5K]

Answer :

The correct answer is due to incorrect position of thermometer .

Distillation is process of separating two volatile liquids on the basis of their boiling points .In involves the following set up ( shown in image )

Since the Boiling point is found is 116-117 C which is near to 124 C , also the purity was checked and thermometer was calibrated .

So the only error could be possible is position of thermometer .

The position of bulb of thermometer is very important to get an accurate reading of boiling point .The vapor so formed should touch the side walls of bulb as soon as they are formed .

May be the bulb of thermometer was kept far from the vapors formed by liquid so, s<u>ome of the vapor before reaching to bulb start condensing and their Temperature decreases </u>.

Hence , the temperature shown by thermometer was decrease than actual boiling point due to incorrect position of thermometer.

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3 years ago

A rectangular swimming pool is 6 ft deep. One side of the pool is 4.5 times longer than the other. The amount of water needed to

marishachu [46]

I don’t know but let me bless your eyes with this photo

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3 years ago

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Mole ratio of co2 carbonate to water

tino4ka555 [31]

Pls make ur question alittle clearer by may be saying the chemical compound or writing the required reaction

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3 years ago

Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer

notsponge [240]

Answer:

C₃H₄O₂ → 50% C; 5.5 % H; 44.5% O

C₄H₆O₂ → 56 % of C; 7 % of H; 37% of O

C₃H₃N → 68 % of C; 6 % of H; 26 % of N

Explanation:

We determine the molar mass of each compound:

C₃H₄O₂ → 72 g/mol

In 1 mol of acrylic acid (72 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

4 moles of H → 1 g/mol . 4 mol = 4 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 36 / 72 = 50 % of C

4 . 100 / 72 = 5.5 % of H

32 . 100 / 72 = 44.5 % of O

C₄H₆O₂ → 86 g/mol

In 1 mol of methyl acrylate (86 g), we have:

4 moles of C → 12 g/mol . 4 mol = 48 g of C

6 moles of H → 1 g/mol . 6 mol = 6 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 48 / 86 = 56 % of C

6 . 100 / 86 = 7 % of H

32 . 100 / 86 = 37 % of O

C₃H₃N → 53 g/mol

In 1 mol of acrylonitrile (53 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

3 moles of H → 1 g/mol . 3 mol = 3 g of H

1 mol of N → 14g/mol . 1 mol = 14 g of N

Then in 100 g of salt, we may have:

100 . 36 / 53 = 68 % of C

3 . 100 / 53 = 6 % of H

14 . 100 / 53 = 26 % of N

3 0

3 years ago