The balanced half-cell equation for the reaction occurring at the anode is H2 ---> 2H(+) + 2e(-)
E<u>xplanation:</u>
- The balanced half-cell equation taking place at the anode is explained below
- The product produced in the reaction in the fuel cell is water.
- H2 ---> 2H(+) + 2e(-)
- In the above reaction, the oxidation state of hydrogen switches from 0 to +1.
- It is becoming oxidized by delivering two electrons at the anode.
- In the fuel cell, hydrogen molecules get oxidized to hydronium ions.Thus half-reaction is the oxidation reaction.
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Positive unless your mean to them then everyones negative towards you.
Copper oxide(solid) + Sulphuric Acid (aqueous)-> Copper Sulphate (aqueous)+ Water(liquid)
In equation form:
CuO +H2SO4 -> CuSO4 + H2O
The colour change you will see is black to blue as Copper oxide is usually found as a black powder. Upon the reaction with sulphuric acid it will change to a cyan blue.
If you heat the made solution of copper sulphate, the water will evaporate and you will be left with white anhydrous copper sulphate crystals.
Pure water may be identified by its density: it will have the lowwest density of the three solutions, given that the solutes (salt and sugar) increase the density (this is the easiests and quickest way).
You can also measure the freezing points or boling points to identify the pure water because the solutes depress the freezing points and increase the boling points.
To differentiate sugar water and salt water, you can probe which one conducts electricity, because salt water is a conductor (given that it ionizes into Na+ and Cl-) but sugar water is not a conductor.
Dang bro that stuff is really hard I’m defiantly on a lower grade lol
