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Ksju [112]
2 years ago
13

HElp i am stuck and i am not sure

Chemistry
1 answer:
alexandr1967 [171]2 years ago
7 0

Answer:

B

Explanation:

hope this helps...

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0.3287 g x 45.2 g =?
murzikaleks [220]

Answer:

The exact answer is 14.85724 grams. Just simply multiply these two numbers together to get your answer in grams. No fancy formula is needed for this! Hopefully this helps!

Feel free to mark brainliest!

4 0
2 years ago
Read 2 more answers
Investigate: Press Reset. Start with 2.000 moles of sulfur, then press Start. How many atoms do you think this amount represents
Scilla [17]

Answer:

1.204428 * 10^24 atoms

Explanation:

Number of moles = 2 mol

Number of atoms = ?

The relationship between moles and atoms is given by the avogadro's umber. This is the number of units in one mole of a substance.  The units can be atoms, ions etc In this case it is atoms. The number is equal to  6.02214076 * 10^23

This means;

1 mol = 6.02214076 * 10^23

2 mol = x

Upon solving for x,

x = 2 * 6.02214076 * 10^23

x = 12.04428 * 10^23

x = 1.204428 * 10^24 atoms

6 0
2 years ago
Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume
pishuonlain [190]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

             mass = 0.508 g,               Volume = 0.175 L

             Temperature = (25 + 273) K = 298 K,       P = 1 atm

As per the ideal gas law, PV = nRT.

where,  n = no. of moles = \frac{mass}{\text{molar mass}}

Hence, putting all the given values into the ideal gas equation as follows.

               PV = \frac{mass}{\text{molar mass}} \times RT            

           1 atm \times 0.175 L = \frac{0.508 g}{\text{molar mass}} \times 0.0821 L atm/ K mol \times 298 K  

                            = 71.02 g

As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of Cl_{2} is 70.8 g/mol or 71 g/mol (approx).

Thus, we can conclude that the gas is most likely chlorine.

4 0
3 years ago
When 0.250 moles of KCl are added to 200.0 g of water in a constant pressure calorimeter a temperature change is observed. Given
777dan777 [17]

Explanation:

Upon dissolution of KCl heat is generated and temperature of the solution raises.

Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.

             17.24 kJ/mol \times 0.25 mol

                = 4.31 kJ

or,             = 4310 J      (as 1 kJ = 1000 J)

Mass of solution will be the sum of mass of water and mass of KCl.

       Mass of Solution = mass of water + (no. of moles of KCl × molar mass)

                                    = 200 g + (0.25 mol \times 54.5 g/mol)

                                    = 200 g + 13.625 g

                                    = 213.625 g

Relation between heat, mass and change in temperature is as follows.

                             Q = mC \Delta T

where,    C = specific heat of water = 4.184 J/g^{o}C

Therefore, putting the given values into the above formula as follows.

                     Q = mC \Delta T

            4310 J = 213.625 g \times 4.184 J/g^{o}C \times \Delta T      

              \Delta T = 4.82^{o}C

Thus, we can conclude that rise in temperature will be 4.82^{o}C.

6 0
3 years ago
When the temperature of the air is 25°C, the velocity of a sound wave traveling through the air is approximately
Vitek1552 [10]

Answer ; The correct answer is : 346 m/s .

Sound is a type of longitudinal wave , which is produced when a matter compress or refracts .

Speed of sounds depends on factors like medium , density , temperature etc .

Effect of Temperature on speed of sounds :

When the temperature increases , molecules gains energy and they starts vibrating and with higher temperature vibration becomes fast . So the waves of sounds can travel faster due to faster vibrations . Hence , speed of sounds is directly proportional to the temperature or speed of sounds increases with increase in temperature .

The speed of sounds at 0⁰C is 331 \frac{m}{s}

The relation between speed of sound and temperature is given as :

V = 331 \frac{m}{s}  + ( 0.6 \frac{m}{s- ^0C} * T  )

Given : Temperature = 25 ⁰ C

Plugging values in formula =>

V = 331 \frac{m}{s} + (0.6 \frac{m}{s-^0C}  * 25^0C)

V = 331 \frac{m}{s} + 15 \frac{m}{s}

V =  346 \frac{m}{s}

7 0
3 years ago
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