Answer:
20 mangoes.
Step-by-step explanation:
Given:
Total number of mangoes, a trader bought = ![x](https://tex.z-dn.net/?f=x)
A trader bought at the rate of 4 mangoes for 10 naira.
Five of the mangoes were bad.
He sold the remaining at the rate of 5 mangoes for 20 naira.
He made a gain of 10 naira
Question asked:
Total number of mangoes, a trader bought =
= ?
Solution:
Unitary method
Cost price of 4 mangoes = 10 naira.
Cost price of 1 mango = ![\frac{10}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B4%7D)
Cost price of
mango = ![\frac{10}{4}\times x= \frac{5}{2} x](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B4%7D%5Ctimes%20x%3D%20%5Cfrac%7B5%7D%7B2%7D%20x)
As 5 of the mangoes were bad and he sold the remaining mangoes, then Total number of mangoes sold = ![x-5](https://tex.z-dn.net/?f=x-5)
Sale price of 5 mangoes = 20 naira
Sale price of 1 mango = ![\frac{20}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B5%7D)
Sale price
of mango = ![\frac{20}{5}\times(x-5)=4(x-5)=4x-20](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B5%7D%5Ctimes%28x-5%29%3D4%28x-5%29%3D4x-20)
Now, as we know,
![Gain = Sale price - cost price](https://tex.z-dn.net/?f=Gain%20%3D%20Sale%20price%20-%20cost%20price)
![10 = 4x-20 -\frac{5}{2} x\\ 10=4x-\frac{5}{2} x-20\\10=\frac{8x-5x}{2} -20](https://tex.z-dn.net/?f=10%20%3D%204x-20%20-%5Cfrac%7B5%7D%7B2%7D%20x%5C%5C%2010%3D4x-%5Cfrac%7B5%7D%7B2%7D%20x-20%5C%5C10%3D%5Cfrac%7B8x-5x%7D%7B2%7D%20-20)
![10 =\frac{3x}{2} -20](https://tex.z-dn.net/?f=10%20%3D%5Cfrac%7B3x%7D%7B2%7D%20-20)
Adding both sides by 20
![30=\frac{3x}{2}](https://tex.z-dn.net/?f=30%3D%5Cfrac%7B3x%7D%7B2%7D)
Multiplying both sides by 2
![60 = 3x](https://tex.z-dn.net/?f=60%20%3D%203x)
Dividing both sides by 3
![x=20](https://tex.z-dn.net/?f=x%3D20)
Therefore, total number of mangoes, a trader bought is 20.
C because three tennis balls can fit Inside it making the container slightly bigger
Answer: this is wrong but i need answers sorry
Step-by-step explanation:
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