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Leona [35]
3 years ago
8

Explain why copper metal cannot be used to prepare hydrogen gas​

Chemistry
2 answers:
JulijaS [17]3 years ago
7 0
Because copper is too reactive xx
My name is Ann [436]3 years ago
5 0

Answer: Copper is a less reactive metal, hence does not react with any acid. ... But Cu does not react with HCl because the reduction potential of Cu is higher than that of hydrogen. Only metals which have their reduction potential less than that of hydrogen react with non – oxidising acids.

Explanation:

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3 years ago
NaCl is 0.85% m/v calculate molarity ​
skelet666 [1.2K]

Answer:

For example, 0.9% NaCl contains 0.9 g NaCl per 100 ml of solution or 9 g NaCl/l. This can be converted to molarity by dividing by molecular weight: 0.9% NaCl = (9g/l)/(58.5g/mole) = 0.15 M NaCl.

4 0
3 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\
Leviafan [203]

Answer:

 4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

Explanation:

From the question we are told that

  The number of moles of  is  n =  4.90  \ mols

The formation reaction of Mg(ClO_4)_2  is

             Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2  

From the reaction we see that

   1 mole of  Mg(ClO_4)_2  is formed by 2 moles of Cl^{-} 1 mole of  Mg^{2+} and 4  O^{2-}

 This implies that

   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

                                                    (1 * 4.90) moles of Mg^{2+} and

                                                    (8 * 4.90) moles of  O^{2-}

So

  4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

                           

4 0
3 years ago
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The formula StartFraction actual yield over theoretical yield EndFraction. is used to calculate the ____ yield of a reaction.
Drupady [299]

Answer:

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Explanation:

3 0
4 years ago
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When iron nail is ground into powder, it’s mass
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Answer:

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Explanation:

please mark this answer as brainliest

5 0
4 years ago
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