The answer to the question is b
You have to solve 3 equations pretty much simultaneously here using the x and y values in the general form of the quadratic equation
![y=a x^{2} +bx+c](https://tex.z-dn.net/?f=y%3Da%20x%5E%7B2%7D%20%2Bbx%2Bc)
Start with the first values of x=0 and y=5.1 to solve for c:
![5.1=a(0) ^{2} +b(0)+c](https://tex.z-dn.net/?f=5.1%3Da%280%29%20%5E%7B2%7D%20%2Bb%280%29%2Bc)
so c = 5.1
Next use the second x and y values along with the value of c in the next equation:
![3.03=a(1) ^{2} +b(1)+5.1](https://tex.z-dn.net/?f=3.03%3Da%281%29%20%5E%7B2%7D%20%2Bb%281%29%2B5.1)
gives you
-2.07 = a + b. Solve this for a:
a = -2.07 - b
Finally use the third set of numbers with the c value AND the subbed value for a:
![1.17=a(3) ^{2} +b(3)+5.1](https://tex.z-dn.net/?f=1.17%3Da%283%29%20%5E%7B2%7D%20%2Bb%283%29%2B5.1)
1.17 = 9(-2.07 - b)+ 3b + 5.1 which simplifies to:
1.17 = -18.63 - 9b + 3b + 5.1 which further simplifies to:
14.7 = -6b and b = -2.45
Now you have c and b, let's find a using one of the simplified equations:
-2.07 = a + b
-2.07 = a - 2.45
a = .38
So here's your equation:
Answer:
c: x-3=5
Step-by-step explanation:
what grade is this for?
hope this helps
This problem is basically asking:
![\frac{5}{19} =\frac{x}{250}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B19%7D%20%3D%5Cfrac%7Bx%7D%7B250%7D%20)
Which would mean ![x=\frac{5*250}{19}=\frac{1250}{19}](https://tex.z-dn.net/?f=%20x%3D%5Cfrac%7B5%2A250%7D%7B19%7D%3D%5Cfrac%7B1250%7D%7B19%7D%20)
Move the decimal places, the answer is 6.7 x 10^6