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ddd [48]
3 years ago
6

Lol whats the answer to the question tho lol

Chemistry
1 answer:
pickupchik [31]3 years ago
4 0

Answer:

What do you mean???

Explanation:

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what is the atomic number of an element with a atomic weight of 77cwnd 55 neutrons? Please help fast!
Ronch [10]

Answer:

the atomic number of the element with 77 as atomic weight and 55 neutrons is 22

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3 years ago
Determine the number of moles of gas contained in a 1.25 L container at 25 degrees Celsius and 800 torr
tiny-mole [99]
You would have to use the ideal gas law: PV = nRT where,

P = pressure
V = volume
n = moles
R = universal gas constant for a specific pressure (in this case it's 62.364 torr)
T = temperature in Kelvin

First, convert Celsius to kelvin by adding 273 to 25, which gives you 298K

Now plug in your variables to find n:

(800 torr)(1.25 L) = n(62.364)(298K)

1000 = 18584.472n

Now divide 1000 by 18584.472 to get n:

1000/18584.472 = 0.054 moles
8 0
3 years ago
Based on what you have read, what would be another example of kinetic energy?
Novay_Z [31]
A hammer falling off a table because it’s moving
3 0
3 years ago
Read 2 more answers
Which of the following generally results when the Senate and the House of Representatives pass different versions of the same bi
frutty [35]
The two legislative bodies form a conference committee 
5 0
4 years ago
Standard reduction potentials for zinc(II) and copper(II) The standard reduction potential for a substance indicates how readily
givi [52]

The question is incomplete, the complete question is:

Standard reduction potentials for zinc(II) and copper(II)

The standard reduction potential for a substance indicates how readily that substance gains electrons relative to other substances at standard conditions. The more positive the reduction potential, the more easily the substance gains electrons. Consider the following:

Zn2+(aq)+2e−→Zn(s),Cu2+(aq)+2e−→Cu(s), E∘red=−0.763 V E∘red=+0.337 V

Part B

What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.

Express your answer to three decimal places and include the appropriate units.

Answer:

1.100 V

Explanation:

E∘cell= E∘cathode - E∘anode

E∘cathode= +0.337 V

E∘anode= −0.763 V

E∘cell= 0.337-(-0.763)

E∘cell= 1.1V

4 0
3 years ago
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