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3 years ago

12

A tree 6m high casts a shadow 4m long. What angle do the sun's rays make with the ground?

1 answer:

Usimov [2.4K]3 years ago

7 0

Answer:

tan x° = 56.31°

Step-by-step explanation:

6/4= 1.5

hence x° = 56.31

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The perimeter of a rectangle is 200 yards. What are the dimensions of the rectangle if the length is 60 yards more than the wid

puteri [66]

Answer:

L=80

W=20

Step-by-step explanation:

Perimeter = 2×L+2×w

L=w+60

Perimeter - 2×60 = 4×w

200-120 = 80

80/4= w = 20

L=w+60 = 80

8 0

3 years ago

The quantities x and y are proportional.

irga5000 [103]

Answer:

r=1/4

Step-by-step explanation:

y=1/4*x

2=1/4*8

1/4*8=2

8 0

3 years ago

Read 2 more answers

What is the y-coordinate of the solution for the system of equations? x−y=−11 y+7=−2x

ICE Princess25 [194]

Answer:

$y= 5$

Step-by-step explanation:

Given the system of equations:

$x-y=-11$

$y+7=-2x$

In order to find the y coordinate of the solution we must first find the solution to this system of equations. We first start by solving one of the given equations and then substitute the answer of that into the second equation and further solve to get the final answers.

$x=y=-11$

$y+7=-2x$

$y+7=-2x$

$+ -7$

$y = -2x - 7$

$x - y = -11$

$y = -2x-7$

$x-(-2x-7)=-11$

$x--2x=x+2x=3x$

$3x+7=-11$

$-7$

$-11+-7=-18$

$3x=-18$

$\div3$

$-18\div3=-6$

$x=-6$

$y=-2x-7$

$y=(-2)(-6)-7$

$-2\times-6=12-7=5$

$y=5$

Hope this helps.

7 0

2 years ago

A coin contains 1.25 grams of nickel and 3.75 grams of copper, for a total weight of 5 grams what percentage of the metal in coi

Citrus2011 [14]

3.75/5 = .75
.75 X 100 = 75
75% is the answer

7 0

3 years ago

Read 2 more answers

Log16^*+log4^*+log2^*=7

ale4655 [162]

Answer:

$x = 16$

Step-by-step explanation:

Given

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Required

Solve for x

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Change base of 16 and base of 4 to base 2

$\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7$

Express 16 and 4 as 2^4 and 2^2 respectively

$\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7$

The above can be rewritten as:

$\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7$

$log_22 = 1$

So, we have:

$\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7$

$\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7$

Multiply through by 4

$4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4$

$log_2(x) + 2}log_2(x) + 4log_2(x) = 28$

$7log_2(x) = 28$

Divide through by 7

$\frac{7log_2(x)}{7} = \frac{28}{7}$

$log_2(x) = 4$

Apply the following law of logarithm:

<em>If </em> $log_ab = c$ <em> </em><em>Then </em> $b = a^c$ <em></em>

So, we have:

$x = 2^4$

$x = 16$

6 0

3 years ago