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Oksanka [162]
3 years ago
14

Solve The Following Expression..#No Spam..​​

Mathematics
2 answers:
tankabanditka [31]3 years ago
8 0

Answer:

{ \tt{ \frac{x + 0.25}{3} - 0.5 = x }} \\  \\ { \tt{ \frac{x + 0.25}{3}  = x + 0.5}} \\  \\ { \tt{x + 0.25 = 3(x + 0.5)}} \\  \\ { \tt{x + 0.25 = 3x + 1.5}} \\  \\ { \tt{3x - x = 0.25 - 1.5}} \\  \\ { \tt{2x = -1.25}} \\  \\ { \boxed{ \boxed{ \tt{ \:  \: x = -0.625 \:  \: or \:  \:  -\frac{5}{8} }}}}

Rainbow [258]3 years ago
4 0

\\ \sf\longmapsto \dfrac{x+0.25}{3}-0.5=x

\\ \sf\longmapsto \dfrac{x+0.25-1.5}{3}=x

\\ \sf\longmapsto x-1.25=3x

\\ \sf\longmapsto x-3x=1.25

\\ \sf\longmapsto -2x=1.25

\\ \sf\longmapsto x=\dfrac{1.25}{-2}=-0.625

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Ira Lisetskai [31]
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The easiest way is to simply divide 3.5 by 4; this will tell you how many liters were lost each of those four days.

The other way does the same thing, but a little more algebraically...
3.5 liters per day were lost- this can be written as a ratio: 3.5 liters/ 4 days.
You need to solve for x liters/ 1 day.
Since these are equivalent, you set them equal to each other: 
\frac{3.5 liters}{4 days} =  \frac{x liters}{1 day}
From here, you can cross multiply to get 3.5=4x
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Since the variable x represented the number of liters lost in 1 day, you can write your answer as 1.5 liters. 

So, the simple answer is: the average change in the water volume each day was 1.5 liters. 
8 0
4 years ago
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Step-by-step explanation:

Given

height of cone A and B  h_a=h_b=5\ in.

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The volume of cone A

V_a=\dfrac{1}{3}\pi r_a^2h_a=20.9\quad \ldots(i)

The volume of cone B

V_b=\dfrac{1}{3}\pi r_b^2h_b=4\times 20.9\quad \ldots(ii)

divide (i) and (ii) we get

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Answer:

y = 3 ( x + 2 ) 2 − 4

Step-by-step explanation:

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