Find the values of p and q such that 4x^2+12=4(x-p)^2+q !!!!!
1 answer:
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Answer:
The area of rectangle is 98 ft.sq.
Step-by-step explanation:
We are given one length of a rectangular garden lies along a patio wall.
Let the width of garden be x
Length of garden = Twice its width=2x
Length garden enclosed by fencing =l+2b=2x+2x= 4x
We are given that the rest of the garden is enclosed by 28 feet of fencing.
So,4x=28
x=7
Width of garden = 7 feet
length of garden = 2x=2(7)=14 feet
Area of garden =
Hence The area of rectangle is 98 ft.sq.
The expected frequency of east campus and passed is C. 42 students
<h3>How to calculate the value?</h3>The table for expected frequency is ,
East Campus West Campus Total
Passed (84*100)/22=42 (84*100)/200 =42 84
Failed (116*100)/200=58 (116*100)/22=58 116
Total 100 100 200
Passed = 84×100/200
= 42
Therefore, the expected frequency of East Campus and Passed is 42 students.
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