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3 years ago

9

What should be done if a spectrophotometer reports an absorbance that is too high?

1 answer:

bija089 [108]3 years ago

7 0

Absorbance values greater than or equal to 1.0 are too high. If you are getting absorbance values of 1.0 or above, your solution is too concentrated. Simply dilute your sample and recollect data . Keep in mind that absorbance is the logarithm of the transmission (T) of light through a sample

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Which one accelerates more if the same amount of force is used? <br>

jonny [76]

Two objects are dropped from a height of 100 m.
If one object is heavier than the
other object, which of the following is true?
(Note: ignore air resistance)
(a) The heavier object will experience equal force
and accelerate more slowly.
(b) The heavier object will experience more force
and accelerate more quickly
(c) The heavier object will experience equal force
and accelerate at the same rate
(d) The heavier object will experience more force
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2 years ago

Li + HNO3 > LiNO3 + H2 how do I balance it? Show work pls

azamat

Answer: The balanced equation is $2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$ .

Explanation:

The given reaction equation is as follows.

$Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}$

Number of atoms present on reactant side are as follows.

Li = 1
H = 1
$NO_{3}$ = 1

Number of atoms present on product side are as follows.

Li = 1
H = 2
$NO_{3}$ = 1

To balance this equation, multiply Li by 2 and $HNO_{3}$ by 2 on reactant side. Also, multiply $LiNO_{3}$ by 2 on product side.

Hence, the equation can be rewritten as follows.

$2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$

Now, number of atoms present on reactant side are as follows.

Li = 2
H = 2
$NO_{3}$ = 2

Number of atoms present on product side are as follows.

Li = 2
H = 2
$NO_{3}$ = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is $2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$ .

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3 years ago

A 13.97 g sample of nabr contains 22.34% na by mass. Considering the law of constant composition (definite proportions) how many

Grace [21]

As per the law of constant composition, a given sample will always contain the same number of elements that combine in the same mass proportion.

Therefore if a sample of 13.97 g of NaBr contains 22.39 % of Na by mass then, a sample of 5.75 g of NaBr would also contain 22.39% Na by mass

Hence:

Mass of Na = 5.75 g * 22.39/100 = 1.287 g

5.75 g of NaBr would contain 1.29 g of Na

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3 years ago

After rigorous statistical analyses have shown a very low likelihood (usually 5% or less) of a result having occurred by chance

PSYCHO15rus [73]

Answer:

Statistically significant.

Explanation:

The common example is tossing a coin.

The probability of tossing a head is $\frac{ 1}{ 2} = 50 \%$ .

The probability of tossing five heads in a row is $(\frac{1}{2})^{5} = \frac{1 }{ 32} = 3.1 \%$ .

p < 5 %, so this is a <em>statistically significant</em> result.

if someone tossed five successive heads, I would start thinking that the coin was loaded.

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3 years ago

Read 2 more answers

An example of energy conversion from kinetic to thermal energy would be

Sergeu [11.5K]

Dropping a water balloon on the ground

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