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RUDIKE [14]
4 years ago
11

Ultraviolet radiation and radiation of shorter wavelengths can damage biological molecules because they carry enough energy to b

reak bonds within the molecules. A carbon-carbon bond requires 348 kJ/mol to break.What is the longest wavelength of radiation with enough energy to break carbon-carbon bonds?
Chemistry
1 answer:
Kamila [148]4 years ago
5 0

Answer:

344 nm is the longest wavelength of radiation with enough energy to break carbon-carbon bonds.

Explanation:

C-C(g)\rightarrow 2C(g) ,ΔH = 348 kJ/mol

Energy required to break 1 mole of C-C bond = 348 kJ

Energy required to break 1 C-C bond = E

E = \frac{348,000J}{6.022\times 10^{23}}=5.779\times 10^{-19} J

Energy related with the wavelength of light is given by Planck's equation:

E=\frac{hc}{\lambda }

\lambda =\frac{hc}{E}

=\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{5.779\times 10^{-19} J}

\lambda =3.44\times 10^{-7} m = 344 nm

1 m =10^9 nm

344 nm is the longest wavelength of radiation with enough energy to break carbon-carbon bonds.

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A beaker with 1.80×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c
tekilochka [14]

Answer:

The pH change in 0,206 units

Explanation:

When the acetic acid buffer is at pH 5,000; it is possible to obtain the acetate/acetic acid proportions using Henderson-Hasselbalch formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] Where A⁻ is CH₃COO⁻ and HA is CH₃COOH.

Replacing:

5,000 = 4,740 + log₁₀ [A⁻]/[HA]

1,820 = [A⁻]/[HA] <em>(1)</em>

As buffer concentration is 0,100M:

[A⁻] + [HA] = 0,100 <em>(2)</em>

Replacing (2) in (1)

[HA] = 0,035M

And [A⁻] = 0,065M

As volume is 1,80x10²mL, moles of HA and A⁻ are:

0,180L × 0,035M = <em>6,3x10⁻³mol of HA</em>

0,180L × 0,065M = <em>1,17x10⁻²mol of A⁻</em>

The reaction of HCl with A⁻ is:

HCl + A⁻ → HA + Cl⁻

The add moles of HCl are:

0,0065L×0,330M = 2,145x10⁻³ moles of HCl that are equivalent to moles of A⁻ consumed and moles of HA produced.

Thus, moles of HA after addition of HCl are:

6,3x10⁻³mol + 2,145x10⁻³ mol = <em>8,445x10⁻³ moles of HA</em>

And moles of A⁻ are:

1,17x10⁻²mol - 2,145x10⁻³ mol = <em>9,555x10⁻³ moles of A⁻</em>

Replacing these values in Henderson-Hasselbalch formula:

pH = 4,740 + log₁₀ [9,555x10⁻³ ]/[8,445x10⁻³ ]

pH = 4,794

<em>The pH change in </em>5,000-4,794 <em>= 0,206 units</em>

I hope it helps!

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3 years ago
What is the smallest particle of any amount of copper
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4 years ago
Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

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Now we can calculate pH:

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3 0
3 years ago
A 100.0-mL flask contains 0.193 g of a volatile oxide of nitrogen. The pressure in the flask is 760 mmHg at 17°C. Is the gas NO,
cestrela7 [59]

Answer:

NO_2

Explanation:

Considering,  

n=\frac{m}{M}

Using ideal gas equation as:

PV=\frac{m}{M}RT

where,  

P is the pressure  = 760 mmHg

V is the volume  = 100.0 mL = 0.1 L

m is the mass of the gas  = 0.193 g

M is the molar mass of the gas  = ?

Temperature = 17 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (17 + 273.15) K = 290.15 K

R is Gas constant having value = 62.36367 L. mmHg/K. mol

Applying the values as:-

760\times 0.1=\frac{0.193}{M}\times 62.36367\times 290.15

M = 45.95 g/mol

This mass corresponds to NO_2. Hence, the gas must be NO_2.

7 0
3 years ago
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