We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
Answer:
5x+10
Step-by-step explanation:
Distribute:
=(5)(x)+(5)(3)+−5
=5x+15+−5
Combine Like Terms:
=5x+15+−5
=(5x)+(15+−5)
=5x+10
Answer:
C
Step-by-step explanation:
Using the sine ratio in the right triangle.
sinC = 
= 
= 
, thus
∠ C = 
( ) ≈ 34.85° ( to 2 dec. places )
Answer:
Step-by-step explanation:
We have been given that the rectangle has an area of 
square meters and a length of 
. We are asked to find the width of rectangle.
Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.
Upon substituting our given values in above formula we will get,
Using exponent rule for quotient 
we will get,
Therefore, width of our given rectangle will be 9x meters.
