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3 years ago

Where do trees really come from and this is my little sister asking it not me

Physics

2 answers:

Hoochie [10]3 years ago

7 0

The trees come from a seed and grow to trees

salantis [7]3 years ago

5 0

Trees start from a seed that then break the seed and gets out and grows roots that then starts making the inner layers of the tree and the bark (the outside of a tree) it then grows its leaves and creates more seeds that fall and make other trees and from then on it keeps growing larger until it can't grow no more. If you wanna know how old a tree is you can chop it down and you'll see rings if you count those rings that's how many years the tree has been growing for. Hope this helps you're little sister

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A very small tilt in Earth’s axis would likely cause ____.

olchik [2.2K]

If the Earth's axis were closer to "straight up and down" than
the present 23.5°, then . . .

-- The areas around the north and south poles where the sun
can be up or down for more than 24 hours would be smaller.

-- The "Tropic Zone", between the Tropic of Cancer and the
Tropic of Capricorn, where it's possible for the sun to be
directly overhead, would be narrower.

-- There would be less difference, everywhere, between the
lengths of daylight on the "longest day" and the "shortest day"
of the year.

-- The seasons would be less extreme everywhere. There would
be less difference, everywhere, between the coldest part of the
Winter and the warmest part of the Summer.

3 0

3 years ago

Read 2 more answers

An elevator cab is pulled directly upward by a single cable. The elevator cab and its single occupant have a mass of 2300 kg. Wh

Murrr4er [49]

Answer:

15.64 KN

Explanation:

mass of the elevator cab with a single occupant= 2300 kg

acceleration relative to the cab $a_{ce}$ = 6.80 m/s^2

acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2

The acceleration of elevator cab relative to the ground $a_{cg}$

now we can say that

$a_{ce} +a_{eg} =a_{cg}$

=-6.80+ a_{eg}= -9.8

[tex]a_{eg}=-9.8+6.80=-3.8

The forces that act on elevator cab are tension and gravitational, applying newtons second law

T- mg= ma_{eg}

Then the tension in the cable is

T= 2300(-3.8)+2300×9.8= 15640 N= 15.64 KN

therefore tension in the string will be 15.64 KN

3 0

3 years ago

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at

Mashcka [7]

Answer:

The speed of the moving walkway is 1.50 m/s

Explanation:

The position of the child can be calculated using the following equation:

x = x0 + v · t

Where :

x = position of the child at time t.

v = velocity of the child.

t = time.

When the child runs in the same direction as the walkway, the velocity of the child will be its velocity relative to the walkway plus the velocity of the walkway. Then, if we place the origin of the frame of reference at the start of the walkway:

x = x0 + v · t

25 m = 0 m + (2.8 m/s + v) · t₁

Where v is the velocity of the walkway

On its way back, the velocity of the child relative to the walkway is in the opposite direction to the velocity of the walkway. Then:

x = x0 + v · t

0 m = 25 m + (-2.8 m/s + v) · t₂

We also know that t₁ + t₂ = 25 s

Then: t₁ = 25 - t₂

So, we can write the following system of equations:

25 m = (2.8 m/s + v) · (25 s - t₂)

-25 m = (-2.8 m/s + v) · t₂

Let´s take the second equation and solve it for t₂

-25 m / (-2.8 m/s + v) = t₂

Now, let´s replace t₂ in the first equation:

25 m = (2.8 m/s + v) · (25 s + 25 m / (-2.8 m/s + v))

Let´s sum the fraction: 25 s + 25 m / (-2.8 m/s + v)

25 m = (2.8 m/s + v) · (25 s ·(-2.8 m/s + v) + 25 m) / (-2.8 m/s + v)

multiply by (-2.8 m/s + v) both sides of the equation:

25 m(-2.8 m/s + v) = (2.8 m/s + v) · (-70 m + 25 s · v + 25 m)

Apply distributive property:

-70 m²/s +25 m·v = -196 m²/s +70 m·v +70 m²/s -70 m·v +25 s ·v² + 25 m v

56 m²/s = 25 s · v²

56 m²/s / 25 s = v²

v = 1.50 m/s

The speed of the moving walkway is 1.50 m/s

7 0

3 years ago

What causes interstellar dust and clouds into plants and stars

AnnZ [28]

I assume you mean planets eitherway interstellar dust and clouds have solid material and as well as minerals such as iron and over time solid chuncks start to fuse together and make a planet but with stars however it is different because a star has a little solid core surrounded by gasses (hydrogen and helium) to produce heat in a method called nuclear fusion so interstellar clouds contain gasses as well and solids as I previously said and form a star as well

this is from my understanding

5 0

3 years ago

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 4.15 m/sm/s. Her husband Bruce suddenly rea

Darya [45]

Answer:

Explanation:

Distance travelled by Henrietta in 5.5 s = 4.15 x 5.5 = 22.825 m .

Time taken by lunch of bagels to fall vertically by 55.2 m . Let it be t .

s = ut + 1/2 g t²

55.2 = 0 + .5 x 9.8 x t²

t² = 11.26

t = 3.356 s

By the time the lunch of bagels touches the hand of Henrietta , she would have travelled further by distance

s = 3.356 x 4.15 = 13.9 m

She is now at distance of 22.825 + 13.9 = 36.725 m from window .

So lunch of bagels must travel a horizontal distance of 36.725 m in 3.356 s which the time of fall of bagel .

Speed of bagel = distance / time

= 36.725 / 3.356

= 10.94 m /s

b )

Henrietta is 36.725 m from window at the time when she catches the bangel.

6 0

3 years ago