Answer:
(c) 97 dB sound intensity level
Explanation:
We have given the intensity of the loud car horn ![I=0.005w/m^2](https://tex.z-dn.net/?f=I%3D0.005w%2Fm%5E2)
We know that ![I_O=10^{-12}w/m^2](https://tex.z-dn.net/?f=I_O%3D10%5E%7B-12%7Dw%2Fm%5E2)
Now the sound intensity level is given by
, which is nearly equal to 97
So the sound intensity level will be 97 dB
So option (c) will be the correct option
29.213 cm3
First, calculate the mass of the water used. You do this by subtracting the original mass of the flask from the combined mass of the water and flask, giving:60.735 g - 31.601 g = 29.134 g
So we now know we have 29.134 g of water. To calculate the volume of the flask, simply divide by the density of the water, giving:29.134 g / (0.9973 g/cm3) = 29.213 cm3
Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:
![d=\frac{1,280,000,000km}{37,000}=34,594.59km](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%2C280%2C000%2C000km%7D%7B37%2C000%7D%3D34%2C594.59km)
You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:
![v=\frac{d}{t}=\frac{34,594.59km}{90min}=384.38\frac{km}{min}\approx384\frac{km}{min}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D%3D%5Cfrac%7B34%2C594.59km%7D%7B90min%7D%3D384.38%5Cfrac%7Bkm%7D%7Bmin%7D%5Capprox384%5Cfrac%7Bkm%7D%7Bmin%7D)
hence, the speed of the Hubble is approximately 384km/min
the normal force is the force applied opposite to the weight
of the was box. So the normal force is equal to the weight of the box = 24 kg
*(9.81 m/s2) = 235.44 N
the acceleration of the box be solve using newtons 2nd
law of motion:
F = ma
a = F/ m = 585 N/ 24 kg = 24.38 m/s2
If the temperature is high there is less water because it evaporates if it is cloudy it is more because it doesn't evaporate