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ASHA 777 [7]
2 years ago
11

Answer if correct only but please help!!

Mathematics
1 answer:
djyliett [7]2 years ago
3 0

According to above statement the required Inequality will be :

  • 31 + 5.6t < 75.8

  • 5.6t < 75.8 - 31

  • 5.6t < 44.8

  • t <  \dfrac{44.8}{5.6}

  • t < 8

hence, the value of t should be less than 8 hours.

so, they can rent the meeting room for 7 hours.

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PLEASE HELP ME I WILL GIVE BRAINLIST
liq [111]
1)
= 24z^7

answer
A. 24z^7

2)
= 24 x^2y^9

answer
D. 24 x^2y^9

3)
=w^12z^18

answer
C. w^12z^18

4)
= 4x^6

answer
B. 4x^6
4 0
3 years ago
HALLP QUICKKKK
Rina8888 [55]
To solve this we are going to use the formula for speed: S= \frac{d}{t}
where
S is the speed
d is the distance 
t is the time 

Let S_{l} be the speed of the boat in the lake, S_{a} the speed of the boat in the river, t_{l} the time of the boat in the lake, and t_{a} the time of the boat in the river. 

We know for our problem that <span>the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
</span>S_{a}=S_{l}-2
We also know that in the lake the boat<span> sailed for 1 hour longer than it sailed in the river, so:
</span>t_{l}=t_{a}+1
<span>
Now, we can set up our equations.
Speed of the boat traveling in the river:
</span>S_{a}= \frac{6}{t_{a} }
But we know that S_{a}=S_{l}-2, so:
S_{l}-2= \frac{6}{t_{a} } equation (1)

Speed of the boat traveling in the lake:
S_{l}= \frac{15}{t_{l} }
But we know that t_{l}=t_{a}+1, so:
S_{l}= \frac{15}{t_{a}+1} equation (2)

Solving for t_{a} in equation (1):
S_{l}-2= \frac{6}{t_{a} }
t_{a}= \frac{6}{S_{l}-2} equation (3)

Solving for t_{a} in equation (2):
S_{l}= \frac{15}{t_{a}+1}
t_{a}+1= \frac{15}{S_{l}}
t_{a}=\frac{15}{S_{l}}-1
t_{a}= \frac{15-S_{l}}{S_{l}} equation (4)

Replacing equation (4) in equation (3):
t_{a}= \frac{6}{S_{l}-2}
\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}

Solving for S_{l}:
\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}
(15-S_{l})(S_{l}-2)=6S_{l}
15S_{l}-30-S_{l}^2+2S_{l}=6S_{l}
S_{l}^2-11S_{l}+30=0
(S_{l}-6)(S_{l}-5)=0
S_{l}=6 or S_{l}=5

We can conclude that the speed of the boat traveling in the lake was either 6 km/hour or 5 km/hour.
3 0
4 years ago
-24 divided by x + 12 to the second when x= -14
ELEN [110]

Answer:12

Step-by-step explanation:

3 0
3 years ago
Help how do I do this
Anna71 [15]
This is a form of the Pythagorean Theorem.  We just need to know how far we went in the x direction and how far in the y direction then use
a^2 + b^2 = c^2 to find the value.

distance in the x direction (-4 to -4) that's easy it didn't move. so that is zero and thus would make the distance all in the y direction. 

To move from 8 to -8 we take (8 - (-8)) = 8 + 8 = 16 which is your answer
7 0
3 years ago
Are the following shapes similar?
Diano4ka-milaya [45]

No because they're two separate shapes of different porportions. one is 5 cm x 9 cm and the other is 3 x 7 they're not similar. It's hard to explain but a shape that was 10 cm x 30 cm would be similar to the same shape that was 1 cm x 3 cm's.

5 0
3 years ago
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