1)
= 24z^7
answer
A. 24z^7
2)
= 24 x^2y^9
answer
D. 24 x^2y^9
3)
=w^12z^18
answer
C. w^12z^18
4)
= 4x^6
answer
B. 4x^6
To solve this we are going to use the formula for speed:

where

is the speed

is the distance

is the time
Let

be the speed of the boat in the lake,

the speed of the boat in the river,

the time of the boat in the lake, and

the time of the boat in the river.
We know for our problem that <span>the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
</span>

We also know that in the lake the boat<span> sailed for 1 hour longer than it sailed in the river, so:
</span>

<span>
Now, we can set up our equations.
Speed of the boat traveling in the river:
</span>

But we know that

, so:

equation (1)
Speed of the boat traveling in the lake:

But we know that

, so:

equation (2)
Solving for

in equation (1):


equation (3)
Solving for

in equation (2):




equation (4)
Replacing equation (4) in equation (3):


Solving for

:






or

We can conclude that the speed of the boat traveling in the lake was either
6 km/hour or
5 km/hour.
Answer:12
Step-by-step explanation:
This is a form of the Pythagorean Theorem. We just need to know how far we went in the x direction and how far in the y direction then use
a^2 + b^2 = c^2 to find the value.
distance in the x direction (-4 to -4) that's easy it didn't move. so that is zero and thus would make the distance all in the y direction.
To move from 8 to -8 we take (8 - (-8)) = 8 + 8 = 16 which is your answer
No because they're two separate shapes of different porportions. one is 5 cm x 9 cm and the other is 3 x 7 they're not similar. It's hard to explain but a shape that was 10 cm x 30 cm would be similar to the same shape that was 1 cm x 3 cm's.