Answer:
Volume in L = 0.50 L
Explanation:
Given data:
Molarity of solution = 0.1850 M
Mass of BaCl₂ = 19.30 g
Volume of solution = ?
Solution:
First of all we will calculate the number of moles of solute:
Number of moles = mass/molar mass
Molar mass of BaCl₂ = 208.23 g/mol
Number of moles = 19.30 g / 208.23 g/mol
Number of moles = 0.093 mol
Volume of solution:
Molarity = number of moles of solute / volume of solution in L
0.1850 M = 0.093 mol / Volume in L
Volume in L = 0.093 mol / 0.1850 M (M= mol/L)
Volume in L = 0.50 L
Answer:
The final temperature of water = 22.1224 °C
Explanation:
<u>Step 1</u> : defien the formula for heat transfer
q = m*c*ΔT
with q = heat transfer
with m = mass of the substance
with c = specific heat ( of water in this case)
with ΔT = difference between final temperature and initial temperature
In this case :
q=366kJ = 366 *10^3 J
mass of water = 48kg = 48000g
c= specific heat of wwater = 4.184 J / g °C
initial temperature = 20.3 °C
final temperature = TO BE DETERMINED
<u>Step 2</u>: Calculate temperature
366000 J = 48000g * 4.184J/g °C * (T2 - 20.3)
366000 / (480000 * 4.184) = 1.8224 = (T2 - 20.3)
T2 = 20.3 + 1.82 =22.1224 ° C
The final temperature of water = 22.1224 °C
Answer:
number of moles of water (n) = 1.383 x10 ⁻⁵ mol
Explanation:
Data Given:
No. of molecules of water = 8.33×10¹⁸
No. of Mole of water = ?
Formula Used to calculate
no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number
Avogadro's no. = 6.023 x10²³
So the formula could be written as
no. of moles (n) = no. of molecules of water /6.023 x10²³
Put the values in above formula
no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³
no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³
no. of moles (n) = 1.383 x10 ⁻⁵
so 1.383 x10 ⁻⁵ moles of water are represented by 8.33×10¹⁸ molecules of water.
For 5.43 g/mL and 5.44 g/mL = 0.01 the least diff and most precise.
First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.
For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01
For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07
For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01
For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03
As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.
To know more about precision visit :
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