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2 years ago

14

Why is methane, CH4, a nonpolar compound?

2 answers:

mrs_skeptik [129]2 years ago

8 0

Why is methane, CH4, a nonpolar compound?

The molecule methane has four Carbon-Hydrogen single covalent bonds. These covalent bonds are called nonpolar covalent bonds because. The consequence of this equal sharing of electrons is that there is no charge separation (dipole moment).

Tom [10]2 years ago

6 0

Each covalent H bond is nonpolar.

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If you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of

irakobra [83]

Answer:

0.22

Explanation:

Given, Mass of $C_{18}H_{21}NO_3$ = 46.85 g

Molar mass of $C_{18}H_{21}NO_3$ = 299.4 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{46.85\ g}{299.4\ g/mol}$

$Moles\ of\ C_{18}H_{21}NO_3= 0.1565\ mol$

Given, Mass of $C_{2}H_{5}OH$ = 125.5 g

Molar mass of $C_{2}H_{5}OH$ = 46.07 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{125.5\ g}{46.07\ g/mol}$

$Moles\ of\ C_{2}H_{5}OH= 0.5535\ mol$

So, according to definition of mole fraction:

$Mole\ fraction\ of\ codeine=\frac {n_{codeine}}{n_{codeine}+n_{ethanol}}$

$Mole\ fraction\ of\ codeine=\frac{0.1565}{0.1565+0.5535}=0.22$

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3 years ago

Increasing technology addiction among the youth write a letter to editor

ruslelena [56]

Answer:

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Explanation:

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2 years ago

Which of the following is equal to 1 mole?

nadya68 [22]

They are all equal to one mole (all of the above).

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3 years ago

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Aleks04 [339]

Answer:

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3 years ago

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A chemist needs to find the concentration of a solution of barium hydroxide.

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Method 1: gravimetry

advantages: Impurities in the sample can be identified

disadvantages: The process is long, because it goes through several stages

Method 2: titration

advantages: the process is fast, because the titrate and titrant react immediately

disadvantages: Sometimes the determination of the end point of the titration is carried out too fast or too slowly so that the calculations carried out are inaccurate

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1 year ago