W=Fd. Force is not given so we solve for it. F=ma, m=5kg, a=2m/s^2, F=10N. Distance is not given so we solve for it, x=.5a(t^2)=.5(2)(7x7)=49m. F=10N, d=49m, W=490J.
Pulleys can be used to lift heavy objects that otherwise may not be able to be lifted. They reduce the amount of force it takes to lift a load.
Answer: Yes
The capacitor in an RC circuit (Resistor-Capacitance circuit) creates a time delay that decays exponentially. Therefore when the voltage to the bulb is removed, it takes a long time for the capacitor to completely discharge.
Although the brightness of the bulb will diminish as the capacitor discharges, the bulb will still be lit until the capacitor discharges to a voltage that is too low to sustain visible light (to the human eye) from the bulb.
Answer:
The skidding distance would be doubled
Explanation:
When the truck applies the brakes and slows down, its motion is a uniformly accelerated motion, so its skidding distance can be found by using the suvat equation
where
v = 0 is the final velocity (zero since the truck comes to a stop)
u is the initial velocity
a is the acceleration
s is the skidding distance
The acceleration can also be written as
where F is the force applied by the brakes and m the mass of the truck. Substituting into the previous equation,
We see that the skidding distance is proportional to the mass: therefore, if the mass of the truck is doubled, the skidding distance will double as well.